[英]Python - All list combinations using addition
I have a list that is in this form: ["Name/num1/num2/num3/num4/num5", ...]
我有一个这样的形式的列表:
["Name/num1/num2/num3/num4/num5", ...]
For example: available = ["a/1/2/3/4/5", "b/5/4/3/2/4", "c/4/3/2/1/3"]
例如:
available = ["a/1/2/3/4/5", "b/5/4/3/2/4", "c/4/3/2/1/3"]
I am trying to create every possible combination of items in available
, where the sum of num5 of each item in the combination (eg for a is 5
, for b is 1
, for c is 5
) is less than MAXNUM
(eg 3000). 我试图创建
available
的每个项目组合,其中组合中每个项目的num5之和(例如for a is 5
, for b is 1
, for c is 5
)小于MAXNUM
(例如3000)。
To clarify with an example, the program will create a generator for available
above and MAXNUM = 9
which can be turned into the following list: 为了用一个例子阐明,程序将创建用于发电机
available
上述和MAXNUM = 9
,其可以变成下面的列表:
[["a/1/2/3/4/5", "b/5/4/3/2/4"], ["a/1/2/3/4/5", c/4/3/2/1/3], [b/5/4/3/2/4, b/5/4/3/2/4], [b/5/4/3/2/4, "c/4/3/2/1/3"], ["c/4/3/2/1/3", "c/4/3/2/1/3", "c/4/3/2/1/3"]]
Note: This code needs to return a result with available
having 100 items, and MAXNUM = 3000
within a reasonable time (No more than 10 minutes ideally) 注意:此代码需要在合理的时间内(最好不超过10分钟)返回具有100个项目的
available
结果,且MAXNUM = 3000
Edit: Here is my code in a practical use, as requested: 编辑:这是我的实际要求中的代码:
import itertools
import sys
import time
sys.setrecursionlimit(10000000)
#["Name/Carbs/Protein/Fat/Vitamins/Calories"]
available = ['Fiddleheads/3/1/0/3/80', 'Fireweed Shoots/3/0/0/4/150', 'Prickly Pear Fruit/2/1/1/3/190', 'Huckleberries/2/0/0/6/80', 'Rice/7/1/0/0/90', 'Camas Bulb/1/2/5/0/120', 'Beans/1/4/3/0/120', 'Wheat/6/2/0/0/130', 'Crimini Mushrooms/3/3/1/1/200', 'Corn/5/2/0/1/230', 'Beet/3/1/1/3/230', 'Tomato/4/1/0/3/240', 'Raw Fish/0/3/7/0/200', 'Raw Meat/0/7/3/0/250', 'Tallow/0/0/8/0/200', 'Scrap Meat/0/5/5/0/50', 'Prepared Meat/0/4/6/0/600', 'Raw Roast/0/6/5/0/800', 'Raw Sausage/0/4/8/0/500', 'Raw Bacon/0/3/9/0/600', 'Prime Cut/0/9/4/0/600', 'Cereal Germ/5/0/7/3/20', 'Bean Paste/3/5/7/0/40', 'Flour/15/0/0/0/50', 'Sugar/15/0/0/0/50', 'Camas Paste/3/2/10/0/60', 'Cornmeal/9/3/3/0/60', 'Huckleberry Extract/0/0/0/15/60', 'Yeast/0/8/0/7/60', 'Oil/0/0/15/0/120', 'Infused Oil/0/0/12/3/120', 'Simple Syrup/12/0/3/0/400', 'Rice Sludge/10/1/0/2/450', 'Charred Beet/3/0/3/7/470', 'Camas Mash/1/2/9/1/500', 'Campfire Beans/1/9/3/0/500', 'Wilted Fiddleheads/4/1/0/8/500', 'Boiled Shoots/3/0/1/9/510', 'Charred Camas Bulb/2/3/7/1/510', 'Charred Tomato/8/1/0/4/510', 'Charred Corn/8/1/0/4/530', 'Charred Fish/0/9/4/0/550', 'Charred Meat/0/10/10/0/550', 'Wheat Porridge/10/4/0/10/510', 'Charred Sausage/0/11/15/0/500', 'Fried Tomatoes/12/3/9/2/560', 'Bannock/15/3/8/0/600', 'Fiddlehead Salad/6/6/0/14/970', 'Campfire Roast/0/16/12/0/1000', 'Campfire Stew/5/12/9/4/1200', 'Wild Stew/8/5/5/12/1200', 'Fruit Salad/8/2/2/10/900', 'Meat Stock/5/8/9/3/700', 'Vegetable Stock/11/1/2/11/700', 'Camas Bulb Bake/12/7/5/4/400', 'Flatbread/17/8/3/0/500', 'Huckleberry Muffin/10/5/4/11/450', 'Baked Meat/0/13/17/0/600', 'Baked Roast/4/13/8/7/900', 'Huckleberry Pie/9/5/4/16/1300', 'Meat Pie/7/11/11/5/1300', 'Basic Salad/13/6/6/13/800', 'Simmered Meat/6/18/13/5/900', 'Vegetable Medley/9/5/8/20/900', 'Vegetable Soup/12/4/7/19/1200', 'Crispy Bacon/0/18/26/0/600', 'Stuffed Turkey/9/16/12/7/1500']
global AllSP, AllNames
AllSP = []
AllNames = []
def findcombs(totalNames, totalCarbs, totalProtein, totalFat, totalVitamins, totalNutrients, totalCalories, MAXCALORIES):
doneit = False
for each in available:
each = each.split("/")
name = each[0]
carbs = float(each[1])
protein = float(each[2])
fat = float(each[3])
vitamins = float(each[4])
nutrients = carbs+protein+fat+vitamins
calories = float(each[5])
# print(totalNames, totalCalories, calories, each)
if sum(totalCalories)+calories <= MAXCALORIES:
doneit = True
totalNames2 = totalNames[::]
totalCarbs2 = totalCarbs[::]
totalProtein2 = totalProtein[::]
totalFat2 = totalFat[::]
totalVitamins2 = totalVitamins[::]
totalCalories2 = totalCalories[::]
totalNutrients2 = totalNutrients[::]
totalNames2.append(name)
totalCarbs2.append(carbs)
totalProtein2.append(protein)
totalFat2.append(fat)
totalVitamins2.append(vitamins)
totalCalories2.append(calories)
totalNutrients2.append(nutrients)
# print(" ", totalNames2, totalCarbs2, totalProtein2, totalFat2, totalVitamins2, totalNutrients2, totalCalories2)
findcombs(totalNames2, totalCarbs2, totalProtein2, totalFat2, totalVitamins2, totalNutrients2, totalCalories2, MAXCALORIES)
else:
#find SP
try:
carbs = sum([x * y for x, y in zip(totalCalories, totalCarbs)]) / sum(totalCalories)
protein = sum([x * y for x, y in zip(totalCalories, totalProtein)]) / sum(totalCalories)
fat = sum([x * y for x, y in zip(totalCalories, totalFat)]) / sum(totalCalories)
vitamins = sum([x * y for x, y in zip(totalCalories, totalVitamins)]) / sum(totalCalories)
balance = (carbs+protein+fat+vitamins)/(2*max([carbs,protein,fat,vitamins]))
thisSP = sum([x * y for x, y in zip(totalCalories, totalNutrients)]) / sum(totalCalories) * balance + 12
except:
thisSP = 0
#add SP and names to two lists
AllSP.append(thisSP)
AllNames.append(totalNames)
def main(MAXCALORIES):
findcombs([], [], [], [], [], [], [], MAXCALORIES)
index = AllSP.index(max(AllSP))
print()
print(AllSP[index], " ", AllNames[index])
for i in range(100, 3000, 10):
start = time.time()
main(i)
print("Calories:", i, ">>> Time:", time.time()-start)
Right, so the task for N
foods has time and space complexity of O(exp(N))
. 是的,所以
N
食物的任务在时间和空间上的复杂度为O(exp(N))
。 What you need is some heuristic search like A* (link) which follows some idea of 'how good' one incomplete combination is to direct its further search. 您需要的是一些启发式搜索(例如A *(链接)) ,该搜索遵循某种“不完全组合”是“直接”进行进一步搜索的想法。 As a result you will find not the best solution, but a practical good solution within limited time.
结果,您将不会找到最佳的解决方案,而是在有限的时间内找到切实可行的解决方案。 Alternatives are genetic algorithms, simulated annealing, and other optimization algorithm.
替代方法是遗传算法,模拟退火和其他优化算法。 Note that you must define a metric of how good each combination is!
注意,您必须定义每个组合的好坏的度量!
I was using the package astar
( https://github.com/jrialland/python-astar ) in my video game AI, and it exceeded my expectations. 我在视频游戏AI中使用了
astar
包( https://github.com/jrialland/python-astar ),它超出了我的期望。
Further suggestions: use namedtuple
to make your code more readable, otherwise you will hate finding bugs and extending it: 进一步的建议:使用
namedtuple
使代码更具可读性,否则您将不喜欢查找错误并扩展它:
from collections import namedtuple
food = namedtuple('Food', 'name carbs protein fat vitamins calories')
bananas = food('bananas', 10, 15, 20, 10, 100)
oranges = food('oranges', carbs=10, protein=15, fat=20, vitamins=10, calories=100)
print(bananas.calories, oranges.fat)
Given the high number of possibilities, perhaps you should approach the use of this information differently. 鉴于可能性很大,也许您应该以不同的方式使用此信息。 For example, if the usage context is selection of foods given a prior selection, you could simply provide the information on how many of each food type can be had without going over the maximum
例如,如果使用情况是事先选择食物的选择,则可以简单地提供有关每种食物可以食用多少的信息,而不必超过最大值
foofInfo = [ food.split("/") for food in available ]
foofInfo = { food[0]:tuple([int(v) for v in food[1:]]) for food in available } #name:(carbs,proteins,fat,vitamins,nutrients,calories)
calFood = {}
for name,(_,_,_,_,calories) in foofInfo.items():
if calories not in calFood: calFood[calories] = []
calFood[calories].append(name)
maxCalories = 3000
for calories,foods in calFood.items():
maxCount = maxCalories//calories
print("Up to ",maxCount," of ",", ".join(foods))
So you could propose a progressive refinement of the available options rather than a bazillion combinations: 因此,您可以提议对可用选项进行逐步完善,而不要使用无数组合:
Up to 37 of Fiddleheads, Huckleberries
Up to 20 of Fireweed Shoots
Up to 15 of Prickly Pear Fruit
Up to 33 of Rice
Up to 25 of Camas Bulb, Beans, Oil, Infused Oil
Up to 23 of Wheat
Up to 15 of Crimini Mushrooms, Raw Fish, Tallow
Up to 13 of Corn, Beet
Up to 12 of Tomato
Up to 12 of Raw Meat
Up to 60 of Scrap Meat, Flour, Sugar
Up to 5 of Prepared Meat, Raw Bacon, Prime Cut, Bannock, Baked Meat, Crispy Bacon
Up to 3 of Raw Roast, Basic Salad
Up to 6 of Raw Sausage, Camas Mash, Campfire Beans, Wilted Fiddleheads, Charred Sausage, Flatbread
Up to 150 of Cereal Germ
Up to 75 of Bean Paste
Up to 50 of Camas Paste, Cornmeal, Huckleberry Extract, Yeast
Up to 7 of Simple Syrup, Camas Bulb Bake
Up to 6 of Rice Sludge, Huckleberry Muffin
Up to 6 of Charred Beet
Up to 5 of Boiled Shoots, Charred Camas Bulb, Charred Tomato, Wheat Porridge
Up to 5 of Charred Corn
Up to 5 of Charred Fish, Charred Meat
Up to 5 of Fried Tomatoes
Up to 3 of Fiddlehead Salad
Up to 3 of Campfire Roast
Up to 2 of Campfire Stew, Wild Stew, Vegetable Soup
Up to 3 of Fruit Salad, Baked Roast, Simmered Meat, Vegetable Medley
Up to 4 of Meat Stock, Vegetable Stock
Up to 2 of Huckleberry Pie, Meat Pie
Up to 2 of Stuffed Turkey
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