在“ {}”中具有String / ArrayValue的PowerShell New Pipline变量

Question

I need a solution to create an array in a certain format.

Background I export a SharePoint list and get my fields from an XML file.

The command (via PnP) to export is as follows:

$AllSPListItems = Get-PnPListItem $SharePointListName

$ItemsSelection = @{ L = "ID"; E = { $_["ID"] } },@{ L = "SP_SiteURL"; E = { $_["SP_SiteURL"] } }

$AllSPListItems | Select $ItemsSelection | Export-Csv -Path "C:\Temp\XYZ.csv"

That works, but here's what I want:

$ItemsSelection = @{ L = "$FieldDisplayName[0]"; E = { $_[$FieldURLName[0]] } },@{ L = "$FieldDisplayName[1]"; E = { $_[$FieldURLName[1]] } } }

I get the $FieldDisplayName and $FieldURLName variables from my XML.

Unfortunately I only get the following output:

@{ L = "ID"; E = { $_[$FieldURLName[0]] } },@{ L = "SP_SiteURL"; E = { $_[$FieldURLName[1]] } } }

Name                           Value                                                                                                                                                     
----                           -----                                                                                                                                                     
E                              $FieldURLName[0]                                                                                                                 
L                              ID
E                              $FieldURLName[1]                                                                                                                 
L                              SP_SiteURL

So how can I get the value of "E", not the text? The variables does not resolves.

Thanks a lot!

Answer 1

So how can I get the value of "E", not the text?

You get the text of the E scriptblock because it hasn't executed yet - that only happens once you use it with Select-Object .

To get the correct label names, remove the " quotes around the label expression:

$ItemsSelection = @{ L = $FieldDisplayName[0]; E = { $_[$FieldURLName[0]] } },@{ L = $FieldDisplayName[1]; E = { $_[$FieldURLName[1]] } } }
$AllSPListItems | Select $ItemsSelection | Export-Csv -Path "C:\Temp\XYZ.csv"

Answer 2

Ok i have a solution, is unattractive but apparently there is no other possibility. I use the switch Case:

switch ($FieldDisplayName.Length){

1 {$items | Select @{ L = $FieldDisplayName[0]; E = { $_[$FieldURLName[0]] } } | Export-Csv -Path "C:\install\ExportV1.csv"} 
2 {$items | Select @{ L = $FieldDisplayName[0]; E = { $_[$FieldURLName[0]] } },@{ L = $FieldDisplayName[1]; E = { $_[$FieldURLName[1]] } } | Export-Csv -Path "C:\install\ExportV1.csv"} 

}