对于给定的表，给出每行Oracle SQL的计数

Question

if i have a table like this:

ID  | Name   | Payment
----------------------
101 | Victor | 10
103 | Andy   | 13
134 | Mai    | 2
156 | Chris  | 68
179 | Ryan   | 43

And I wanna have a query that gives out the following

[Count] | ID  | Name   | Payment
----------------------
1       | 101 | Victor | 10
2       | 103 | Andy   | 13
3       | 134 | Mai    | 2
4       | 156 | Chris  | 68
5       | 179 | Ryan   | 43

So it gives out the number of each row but I don't know how to do it ( am a beginner at SQL). Any tips?

Answer 1

Simply use row_number() :

select row_number() over (order by id) as "Count",
       t.*
from t
order by "Count";

You should have both order by s to be sure the numbering on the rows is correct and the order of the rows in the result set is correct.

Answer 2

use dense_rank()

select *,dense_rank() over(order by id) from t

or you could use count()

  select *,count(*) over(order by id) from t

Answer 3

简单

select rownum, ID , Name, Payment from table