如何在里面使用es6函数params？

Question

在这种情况下是否可以使用 es6 函数参数？

 func = param => this.transform(this.targets.param)

Answer 1

Sure. These are just normal functions. The parameters of the functions are available in the scope of the function definition.

 func = param => this.transform(param)

equivalent to

func = param => {
     return this.transform(param);
 }

Answer 2

I assume you have a problem with closures; that is that the "this" does not reference what you would expect ...

Can you try the following:

func = (param, that) => {
     return that.transform(param);
 }

Then call the function with the right context:

func(param, this);