RegExpr 检查字符串是否仅包含 % 或仅包含空格或组合

Question

I am trying to create a regExpr te define if a string contains a % or a whitespace or a combination of the 2.

Example:

'%%%%' ---> true
'%    %%%' ---> true
'test%' ---> false

can someone help?

thx a lot

Answer 1

You can use this regex,

^[% ]+$

Check this JS code demo,

 var arr = ['%%%%','% %%%','test%'] for(s of arr) { console.log(s + ' ---> ' +/^[% ]+$/.test(s)); }