[英]Rename-Item error: Cannot rename because item does not exist
I have the following powershell code, which is attempting to rename all SQL files in a folder, adding a unique prefix to each file eg the first prefix will be '1001 - sp - C - ': 我有以下powershell代码,该代码试图重命名文件夹中的所有SQL文件,并为每个文件添加一个唯一的前缀,例如,第一个前缀将为'1001-sp-C-':
gci -Path 'C:\FolderToLookIn' -Exclude "1*" | ForEach-Object {
New-Object PSObject -Property @{
'LineNumber' = $linenumber;
'Name' = $_.Name;
'Extension' = $_.Extension
};
$linenumber++
} | Where-Object {
$_.Extension -eq ".sql"
} | Rename-Item -NewName {$_.LineNumber.ToString("1000") + ' - sp - C - ' + $_.Name}
However, this produces errors such as the following: 但是,这会产生以下错误:
Rename-Item : Cannot rename because item at '@{Extension=.sql; Rename-Item:无法重命名,因为项目位于'@ {Extension = .sql; LineNumber=22; LineNumber上= 22; Name=sp_Firm_GetAll.sql}' does not exist. 名称= sp_Firm_GetAll.sql}'不存在。
So, how can I add the LineNumber
property and use it as a prefix in the Rename-Item
command without losing the item itself? 因此,如何在不丢失项目本身的情况下添加LineNumber
属性并将其用作Rename-Item
命令中的前缀?
Edit 编辑
I have also tried the following, passing through the FullName
and using this in the Rename-Item
: 我还尝试了以下方法,通过FullName
并在Rename-Item
使用它:
gci -Path 'C:\FolderToSearch' -Exclude "1*" | ForEach-Object {
New-Object psObject -Property @{
'LineNumber' = $linenumber;
'Name' = $_.Name;
'Extension' = $_.Extension;
'FullName' = $_.FullName
};
$linenumber++
} | Where-Object {
$_.Extension -eq ".sql"
} | Rename-Item -Path $_.FullName -NewName {$_.LineNumber.ToString("1000") + ' - sp - C - ' + $_.Name}
However, this errors also: 但是,此错误也会:
Rename-Item : Cannot bind argument to parameter 'Path' because it is null. At line:3 char:19 + Rename-Item -Path $_.FullName -NewName {$_.LineNumber.ToString("1000") + ' - sp
As 如
ForEach
isn't necessary and 重命名项接受管道输入,不需要ForEach
并且 [Ref]
you can increment a counter inside the -NewName {scriptblock}
使用[Ref]
您可以在-NewName {scriptblock}
内增加一个计数器 $Folder = 'C:\FolderToLookIn'
$Count = [ref] 0
Get-ChildItem -Path $Folder -Filter *.sql -File |
Where-Object Name -NotMatch '^\d{4} - sp - C - ' |
Rename-Item -Newname {"{0:1000} - sp - C - {1}" -f $Count.Value++,$_.Name}
A sample folder with A.sql, B.sql, C.sql will have this result: 具有A.sql,B.sql,C.sql的示例文件夹将具有以下结果:
> gci *.sql -name
1000 - sp - C - A.sql
1001 - sp - C - B.sql
1002 - sp - C - C.sql
A variant which first obtains the last/highest number from existing files or sets 1000 as the start. 首先从现有文件中获取最后/最高编号的变量,或将1000设置为开始。
$Count = [Ref][math]::Max(1000,
[int](Get-ChildItem -Path $Folder -Filter *.sql -File|
Where-Object Name -match '^(\d{4}) - sp - C -' |
Select-Object @{n='Count';e={$Matches[1]}} -Last 1).Count)
Get-ChildItem -Path $Folder -Filter *.sql -File |
Where-Object Name -NotMatch '^\d{4} - sp - C - ' |
Rename-item -Newname {"{0:D4} - sp - C - {1}" -f ++$Count.Value,$_.Name}
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