SQL从多个列中选择最接近的值并按最佳顺序排序

Question

My table has 8 columns, let say: My table name is x_table and columns: id, score_1, score_2, score_3, score_4, score_5, score_6, score_7..

Each score_* columns has a score from 0 to 10. Then let say I want to search my table with the following values:

score_1=7, score_2=9, score_3=6, score_4=9, score_5=10, score_6=8, score_7=4.

How do I select this table and display the results according to the best closest values

This below query doesn't give 100% of what I need:

SELECT *
FROM xc_t
WHERE t_id <> 0
    AND t_category1 BETWEEN 0
        AND 11
    AND t_category2 BETWEEN 0
        AND 11
    AND t_category3 BETWEEN 0
        AND 11
    AND t_category4 BETWEEN 0
        AND 11
    AND t_category5 BETWEEN 0
        AND 11
    AND t_category6 BETWEEN 0
        AND 11
    AND t_category7 BETWEEN 0
        AND 11
ORDER BY abs(t_category1 - 6)
    ,abs(t_category2 - 6)
    ,abs(t_category3 - 9)
    ,abs(t_category4 - 2)
    ,abs(tea_category5 - 9)
    ,abs(t_category6 - 4)
    ,abs(t_category7 - 10) limit 0
    ,20

Answer 1

I think you want greatest() :

select t.*, greatest(score_1, score_2, . . ., score_8) as max_score
from t
order by max_score desc;

Is this what you want?

select t.*
from t
order by (abs(score_1 - @score_1) +
          abs(score_2 - @score_2) +
          . . .
          abs(score_7 - @score_7)
         )