[英]How to iterate through and copy double pointer in C
I've created a two dimensional integer array in C, initialised it with values, and then cast it to an int**
(I have to do that because it's for homework). 我已经在C语言中创建了一个二维整数数组,并使用值对其进行了初始化,然后将其转换为
int**
(我必须这样做,因为它是用于家庭作业)。
I've managed to iterate through it and set all of the values to 0. However, when I iterate through it again and print the values it, the output is not all zeros. 我已经设法对其进行迭代并将所有值都设置为0。但是,当我再次对其进行迭代并打印其值时,输出结果并非全为零。
Here is a minimum working example: 这是一个最小的工作示例:
#include <string.h>
#include <stdio.h>
#define ROWS 3
#define COLS 2
int main(void)
{
/* Create array and convert to double pointer */
int c[ROWS][COLS] = {{1,2},{3,5},{8,13}};
int **ptr = (int **)c;
/* Loop through entire array and print then double each value. */
int *temp[ROWS];
for(int i = 0; i<ROWS; i++){
temp[i] = (int*)(ptr+i);
for(int j = 0; j<COLS; j++){
printf("Before setting: %i\n", temp[i][j]);
temp[i][j] = temp[i][j]*2;
}
}
/* Copy temp back into ptr */
memcpy(ptr, temp, sizeof(ptr));
/* Loop through array and print values */
int *temp2[ROWS];
for(int i = 0; i<ROWS; i++){
temp2[i] = (int*)(ptr+i);
for(int j = 0; j<COLS; j++){
printf("After setting: %i\n", temp2[i][j]);
}
}
}
The issue is that the results are not what I would expect. 问题是结果不是我所期望的。 One time I ran it, this was the output:
一次运行它,这是输出:
Before setting: 1
设置前:1
Before setting: 2设定前:2
Before setting: 3设定前:3
Before setting: 5设定前:5
Before setting: 8设定前:8
Before setting: 13设定前:13
After setting: -1193330832设置后:-1193330832
After setting: 32764设置后:32764
After setting: 6设定后:6
After setting: 10设定后:10
After setting: 16设定后:16
After setting: 26设定后:26
The value 32764
is the same every time the program is run, but the value -1193330832
changes each time (I assume it is the memory address of the array). 每次运行程序时,值
32764
都是相同的,但是值-1193330832
每次-1193330832
更改(我假设它是数组的内存地址)。
The output I was expecting is: 我期望的输出是:
Before setting: 1
设置前:1
Before setting: 2设定前:2
Before setting: 3设定前:3
Before setting: 5设定前:5
Before setting: 8设定前:8
Before setting: 13设定前:13
After setting: 1设置后:1
After setting: 4设定后:4
After setting: 6设定后:6
After setting: 10设定后:10
After setting: 16设定后:16
After setting: 26设定后:26
because the values in the first loop have been doubled.因为第一个循环中的值已加倍。
What have I done wrong? 我做错了什么? Why are the values changing and how should I actually go about fixing this?
为什么值会改变,我实际上应该如何解决呢?
(PS the homework doesn't involve finding a way to iterate through the double pointer, but I need to be able to do it to complete the actual task) (PS的作业不涉及寻找一种通过双指针进行迭代的方法,但是我需要能够做到这一点才能完成实际的任务)
int **ptr = (int **)c;
isn't a valid pointer conversion, since you cannot use a pointer-to-pointer to point at a 2D array. 这不是有效的指针转换,因为您不能使用指针对指针指向2D数组。 Because it has nothing to do with 2D arrays.
因为它与2D阵列无关。
Instead you can use a pointer to a 2D array, int (*)[ROWS][COLS];
相反,您可以使用指向2D数组的指针
int (*)[ROWS][COLS];
. 。 The most convenient is however to use a pointer to a 1D array and have it point at the first element of the 2D array:
但是,最方便的方法是使用指向1D数组的指针并将其指向2D数组的第一个元素:
int (*ptr)[COLS] = &c[0];
...
ptr[i][j] = ...;
Fixed example: 固定示例:
#include <string.h>
#include <stdio.h>
#define ROWS 3
#define COLS 2
int main(void)
{
/* Create array and convert to double pointer */
int c[ROWS][COLS] = {{1,2},{3,5},{8,13}};
int (*ptr)[COLS] = &c[0];
/* Loop through entire array and print then double each value. */
for(int i = 0; i<ROWS; i++){
for(int j = 0; j<COLS; j++){
printf("Before setting: %i\n", ptr[i][j]);
ptr[i][j] = ptr[i][j]*2;
}
}
/* Loop through array and print values */
for(int i = 0; i<ROWS; i++){
for(int j = 0; j<COLS; j++){
printf("After setting: %i\n", ptr[i][j]);
}
}
}
(A matter of style, but your order of ROWS and COLS is a bit weird, it is more common to do int[COLS][ROWS]
then for(i=0; i<COLS; i++)
) (关于样式,但是您对ROWS和COLS的顺序有些奇怪,通常先进行
int[COLS][ROWS]
然后再for(i=0; i<COLS; i++)
)
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