如何找到“收藏夹”按钮并使用Selenium WebDriver单击它？

Question

Updated description:

Here is the listing from Redfin.com https://www.redfin.com/CA/Sunnyvale/735-Grape-Ave-94087/home/1835008 , what I want to locate and click is the "Favorite" button on the top-right corner. I've tried the code in the old description as well as all the suggestions by others, but none of them works.

Can someone guide me how to locate the icon in Selenium webdriver?

Thanks a lot!

+++++++++++++++++BELOW IS OLD PROBLEM DESCRIPTION+++++++++++++++++++++++++ I have this button:

<div role="button" title="Favorite" tabindex="0" class="clickable button tertiary-alt" data-rf-test-name="homeControlButton">
<span><svg class="SvgIcon rfSvg favorite svg-icon-off-color" style="height:24px;width:24px"><svg viewBox="0 0 24 24"></svg></svg></span>
</div>

But I tried with find XPath by:

browser.find_element_by_xpath("//*[@class='clickable button tertiary-alt' and @title='favorite']").click()

But it doesn't work. Any help?

Answer 1

Try

browser.find_elements_by_css_selector(".clickable.button.tertiary-alt");

Or you could do

browser.find_elements_by_css_selector("div[title=\"Favorite\"]");

Answer 2

You can use the following XPath:

//div[@title='Favorite']

Hope it helps you!

Answer 3

To click on the element you can target the child <span> tag and you can use either of the following Locator Strategies :

• Using css_selector :

   browser.find_element_by_css_selector("div.clickable.button.tertiary-alt[title='Favorite']>span").click() 

• Using xpath :

   browser.find_element_by_xpath("//div[@class='clickable button tertiary-alt' and @title='Favorite']/span").click() 

Answer 4

Here is the working code.

WebDriverWait(driver,10).until(EC.presence_of_element_located((By.CSS_SELECTOR , "div[data-rf-test-name='abp-favoriteButton'] div[role='button']")))
driver.find_element_by_css_selector("div[data-rf-test-name='abp-favoriteButton'] div[role='button']").click()