虽然语句崩溃 Repl.it (P5.js) 中的选项卡

Question

I have a project due on the 27th, and I have encountered a problem. Repl.it crashes whenever I boot up my program. If you look at my code, on line 42:

//getting a number that isnt the players door or the prize door
  while ((randomDoor2 == prizeDoor) || (randomDoor2 == randomDoor)) {
    setTimeout(
      function(){ 
        randomDoor2 = Math.round(random(1,3));
      }, 
      10000);
  }

there is a while loop. Commenting that out makes the code work perfectly with no lag.

I have no idea what I should try and do.

It might be something other than my while, so here is my entire script.js:

var chance; // swap | dont swap
var prizeDoor;
var randomDoor;
var randomDoor2;
var randomDoor3;
var decide;

function setup() {
  chance = 50;
  createCanvas(1000,1000);
}

function draw() {
 //setting up round

  prizeDoor = Math.round(random(1,3));

  //choosing first door

  console.log("[1] [2] [3]");
  randomDoor = Math.round(random(1,3));

  //showing user the door AI picks
var chance = 50; // swap | dont swap
var prizeDoor;
var randomDoor;
var randomDoor2;
var randomDoor3;
var decide;

function setup() {
  chance = 50;
  createCanvas(1000,1000);
}

function draw() {
 //setting up round

  prizeDoor = Math.round(random(1,3));

  //choosing first door

  console.log("[1] [2] [3]");
  randomDoor = Math.round(random(1,3));

  //showing user the door AI picks

  if (randomDoor == 1) {
    console.log(" ^");
    console.log(" |");
  } else if (randomDoor == 2) {
    console.log("     ^");
    console.log("     |");
  } else {
    console.log("         ^");
    console.log("         |");
  }

  console.log("AI chooses door #" + randomDoor + ".");

  //revealing a door

  //getting a number that isnt the players door or the prize door
  while ((randomDoor2 == prizeDoor) || (randomDoor2 == randomDoor)) {
    setTimeout(
      function(){ 
        randomDoor2 = Math.round(random(1,3));
      }, 
      10000);
  }

  //showing this to the user
  console.log("");
  console.log("Door #" + randomDoor2 + " does not have the prize.");

  //having the computer make a desicion
  if (random(0,100) < chance) {
    decide = "swap doors.";
    while ((randomDoor3 !== randomDoor2) || (randomDoor3 !==  randomDoor)) {
      randomDoor3 = Math.round(random(1,3));
    }
  } else {
    decide = "keep the current door.";
  }

  //letting the user know of the computer's desicion
  console.log("");
  console.log("The AI chose to " + decide);

  // figuring out if the AI won
  if (randomDoor3 == prizeDoor || randomDoor == prizeDoor) {

    console.log("AI won!");

    if (decide == "swap doors.") {
      chance -= 5;
    } else {
      chance += 5;
    }
  } else {

    console.log("AI lost.");

    if (decide == "swap doors.") {
      chance += 5;
    } else {
      chance -= 5;
    }
  }
}

I wanted the while statement to find the door that is not the chosen door nor the door with the prize, but instead it crashes.

Answer 1

Edit i got the code to work did change up a few bits to make it work on my end like the math.random but shouldn't be hard to change back also new to stackoverflow so took me a while to figure out the code snippet pasting :p.

<script type="text/javascript">

var chance; // swap | dont swap
var prizeDoor;
var randomDoor;
var randomDoor2;
var randomDoor3;
var decide;
var chance = 50;
function setup() {
  createCanvas(1000,1000);
}

function draw() {
 //setting up round

  prizeDoor = Math.floor((Math.random() * 3) + 1);
  console.log(prizeDoor+" prizeDoor");

  //choosing first door
  console.log("[1] [2] [3]");
  randomDoor = Math.floor((Math.random() * 3) + 1);
  randomDoor2 = Math.floor((Math.random() * 3) + 1);
  randomDoor3 = Math.floor((Math.random() * 3) + 1);


  //showing user the door AI picks

  if (randomDoor == 1) {
    console.log(" ^");
    console.log(" |");
  } else if (randomDoor == 2) {
    console.log("     ^");
    console.log("     |");
  } else {
    console.log("         ^");
    console.log("         |");
  }



  console.log("AI chooses door #" + randomDoor + ".");


  //revealing a door

  //getting a number that isnt the players door or the prize door
  while ((randomDoor2 == prizeDoor) || (randomDoor2 == randomDoor)) {
   randomDoor2 = Math.floor((Math.random() * 3) + 1);
  }

  //showing this to the user
  console.log("");
  console.log("Door #" + randomDoor2 + " does not have the prize.");

  //having the computer make a desicion
  if (Math.floor((Math.random() * 100) + 1) < chance) {
    decide = "swap doors.";
    while ((randomDoor3 == randomDoor2) || (randomDoor3 == randomDoor)) {
      randomDoor3 = Math.floor((Math.random() * 3) + 1);
    }
  } else {
    randomDoor3 = randomDoor;
    decide = "keep the current door.";
  }

  //letting the user know of the computer's desicion
  console.log("");
  console.log("The AI chose to " + decide);

  // figuring out if the AI won
  if (randomDoor3 == prizeDoor) {

    console.log("AI won!");

    if (decide == "swap doors.") {
      chance -= 5;
    } else {
      chance += 5;
    }
  } else {

    console.log("AI lost.");

    if (decide == "swap doors.") {
      chance += 5;
    } else {
      chance -= 5;
    }
  }
}

draw();
</script>

Answer 2

you are creating two random numbers consecutively prizeDoor & randomDoor, so same numbers to be generated using Math.random on two consecutive hits is quite hard to happen.

In your while loop you are expecting your new random number to match your both previous random numbers now for one hit/compilation they can be same or cannot be if they are not same its useless to have your while loop it will will never terminate,

say a=1 and b=2

now expecting c==a && c==b will never happen cuz a!=b;

changing c in while loop will make no difference. so your logic is completely wrong, let us know what you are trying to achieve maybe then we can help to build up the logic

 let random = () => Math.random() * 3; let prizeDoor = Math.round(random()); console.log('prizeDoor', prizeDoor) let randomDoor = Math.round(random()); console.log('randomDoor', randomDoor)

Answer 3

random() is a method of Math object. It worked for me by replacing all the random() method calls with Math.random().

Answer 4

I figured it out. It was actually pretty easy, just change some operators. Here is the final piece of code:

var chance = 50; // swap | dont swap
var prizeDoor;
var randomDoor;
var randomDoor2;
var randomDoor3;
var decide;

function setup() {
  chance = 50;
  createCanvas(1000,1000);
}

function draw() {
 //setting up round

  prizeDoor = Math.round(random(1,3));

  //choosing first door

  console.log("[1] [2] [3]");
  randomDoor = Math.round(random(1,3));

  //showing user the door AI picks

  if (randomDoor == 1) {
    console.log(" ^");
    console.log(" |");
  } else if (randomDoor == 2) {
    console.log("     ^");
    console.log("     |");
  } else {
    console.log("         ^");
    console.log("         |");
  }

  console.log("AI chooses door #" + randomDoor + ".");

  //revealing a door

  //getting a number that isnt the players door or the prize door
  while ((randomDoor2 == prizeDoor) || (randomDoor2 == randomDoor)) {
    setTimeout(
      function(){ 
        randomDoor2 = Math.round(random(1,3));
      }, 
      10000);
  }

  //showing this to the user
  console.log("");
  console.log("Door #" + randomDoor2 + " does not have the prize.");

  //having the computer make a desicion
  if (random(0,100) < chance) {
    decide = "swap doors.";
    while ((randomDoor3 == randomDoor2) || (randomDoor3 ==  randomDoor)) {
      randomDoor3 = Math.round(random(1,3));
    }
  } else {
    decide = "keep the current door.";
  }

  //letting the user know of the computer's desicion
  console.log("");
  console.log("The AI chose to " + decide);

  // figuring out if the AI won
  if (randomDoor3 == prizeDoor || randomDoor == prizeDoor) {

    console.log("AI won!");

    if (decide == "swap doors.") {
      chance -= 5;
    } else {
      chance += 5;
    }
  } else {

    console.log("AI lost.");

    if (decide == "swap doors.") {
      chance += 5;
    } else {
      chance -= 5;
    }
  }
}