python中的“IndexError：列表索引超出范围”错误

Question

I am new to python. I get an error after running my file. File "C:Users/USER/PycharmProjects/Research/trainer1file (1).py" , line 42, in process iteratorclasses = iter(sorted(os.walk(data))[1])

IndexError: list index out of range

def process(data, mode, batch_size):
    images, labels = list(), list()
    if mode == 'file':
        with open(data) as f:
            data = f.read().splitlines()
        for d in data:
            images.append(d.split(' ')[0])
            labels.append(int(d.split(' ')[1]))
    elif mode == 'folder':
        label = 0
        iteratorclasses = iter(sorted(os.walk(data))[1])
        classes = next(iteratorclasses)
        for c in classes:
            c_dir = os.path.join(data, c)
            iteratorwalk = iter(os.walk(c_dir))
            walk = next(iteratorwalk)
            # Add each image to the training set
            for sample in walk[2]:
                # Only keeps jpeg images
                if sample.endswith('.jpg') or sample.endswith('.jpeg') or sample.endswith('.JPG'):
                    images.append(os.path.join(c_dir, sample))
                    labels.append(label)
            label += 1
    else:
        raise Exception("Unknown mode.")
    images = tf.convert_to_tensor(images, dtype=tf.string)
    labels = tf.convert_to_tensor(labels, dtype=tf.int32)
    image, label = tf.train.slice_input_producer([images, labels],
                                                 shuffle=True)
    x, y = tf.train.batch([image, label], batch_size=batch_size,
                          capacity=batch_size * 8,
                          num_threads=4)
    return x, y

Answer 1

您尝试浏览的目录中可能没有任何内容，这就是索引超出范围的原因。

Answer 2

IndexError: list index out of range

is immediately a warning sign. Just read the error! It says that the l[i] where l is the list and i is the index does not exist since l does not have i or more indices.

eg Let's say I run in Python

l = [1,2,3]
l[1]

What will it return? 2 , of course.
What about l[10] ?

There is no 10th index so it'll return IndexError: list index out of range .

I'll let you away this time, but you just can't give us code and the error and expect us to solve it for you.

Answer 3

sorted() in your case, will return a list with one element, namely a set that contains root dir, list of directories and list of files. therefore the error (because you want to access index 1, so the second element, which is not existing).