错误：应用程序运行失败，尝试实现服务发现尤里卡
[英]Error : Application run failed , trying to implement Service discovery Eureka
问题描述
I have a very simple demo application which I am using to register with Eureka server.
我有一个非常简单的演示应用程序，我用它来注册 Eureka 服务器。 But I am getting the below error.但我收到以下错误。 I have been able to successfully register another demo application but this one fails:我已经能够成功注册另一个演示应用程序，但这个失败了：
This is the error message:这是错误消息：
12:29:07.678 [restartedMain] DEBUG org.springframework.boot.context.logging.ClasspathLoggingApplicationListener - Application failed to start with classpath: [file:/Users/test/Downloads/demorest/target/classes/] 12:29:07.728 [background-preinit] DEBUG org.jboss.logging - Logging Provider: org.jboss.logging.Log4j2LoggerProvider 12:29:07.729 [background-preinit] INFO org.hibernate.validator.internal.util.Version - HV000001: Hibernate Validator 6.0.14.Final 12:29:07.736 [background-preinit] DEBUG org.hibernate.validator.internal.engine.resolver.TraversableResolvers - Cannot find javax.persistence.Persistence on classpath.
The same project can start fine without the Eureka in place.如果没有 Eureka，同一个项目也能顺利开始。
<?xml version="1.0" encoding="UTF-8"?>
<project xmlns="http://maven.apache.org/POM/4.0.0"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.1.2.RELEASE</version>
<relativePath /> <!-- lookup parent from repository -->
</parent>
<groupId>com.example.rest</groupId>
<artifactId>demorest</artifactId>
<version>0.0.1-SNAPSHOT</version>
<name>demorest</name>
<description>Demo project for Spring Boot</description>
<properties>
<java.version>1.8</java.version>
</properties>
<dependencies>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-web</artifactId>
</dependency>
<dependency>
<groupId>org.springframework.cloud</groupId>
<artifactId>spring-cloud-starter-netflix-eureka-client</artifactId>
<version>1.4.6.RELEASE</version>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-devtools</artifactId>
<scope>runtime</scope>
</dependency>
<dependency>
<groupId>com.h2database</groupId>
<artifactId>h2</artifactId>
<scope>runtime</scope>
</dependency>
<dependency>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-test</artifactId>
<scope>test</scope>
</dependency>
</dependencies>
<build>
<plugins>
<plugin>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-maven-plugin</artifactId>
</plugin>
</plugins>
</build>
application.properties:应用程序属性：
spring.application.name=demorest
eureka.client.service-url.defaultZone=http://localhost:8761/eureka
Application class:应用类：
@EnableDiscoveryClient
@SpringBootApplication
public class DemorestApplication {
public static void main(String[] args) {
ApplicationContext ctx = SpringApplication.run(DemorestApplication.class, args);
String[] beanNames = ctx.getBeanDefinitionNames();
//Arrays.sort(beanNames);
for(String name : beanNames)
System.out.println(name);
}
}
1 个解决方案
解决方案1
0 2022-01-03 07:49:24
In addition to the answer given by Ben G , Spring Cloud and Spring Boot should have compatible versions which can be found here under Table 1. Release train Spring Boot compatibility .除了通过给出的答案奔摹，春季云春季启动应该可以找到兼容的版本在这里下表1.释放列车春天启动的兼容性。
For example: Spring Boot 2.6.1 and Spring Cloud 2021.0.0 can be used together as following:例如：Spring Boot 2.6.1 和 Spring Cloud 2021.0.0 可以一起使用如下：
<parent>
<groupId>org.springframework.boot</groupId>
<artifactId>spring-boot-starter-parent</artifactId>
<version>2.6.1</version>
<relativePath /> <!-- lookup parent from repository -->
</parent>
<dependencyManagement>
<dependencies>
<dependency>
<groupId>org.springframework.cloud</groupId>
<artifactId>spring-cloud-dependencies</artifactId>
<version>2021.0.0</version>
<type>pom</type>
<scope>import</scope>
</dependency>
</dependencies>
</dependencyManagement>
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