如何跳过 ash/dash shell 函数中的第一个参数？

Question

In an ash/dash function, I can refer to the full parameter list like this:

allparameters() { echo "$@"; }

Which gives me:

$ allparameters yyyyy abffcd efgh
yyyyy abffcd efgh

I want to skip yyyyy , so I tried ${@:2} :

butlast() { echo "${@:2}"; }

However, this skips the first two characters:

$ butlast yyyyy abffcd efgh
yyy abffcd efgh
$ butlast abffcd efgh
ffcd efgh

I wasn't able to find the colon syntax in the man page for ash, so that may be a bash-ism. What is the equivalent?

Answer 1

${name:offset} is a bash ism, but you can use the POSIX shift command for what you want.

$ butlast() { shift; echo "$@"; }
$ butlast foo bar baz
bar baz