如何生成无限随机数的骰子直到它们相等？

Question

I'm trying to simulate a program that will roll a pair of dice and it will generate the results until the variables are equal, however I can't figure this out.

#include<iostream>
#include<cstdlib>
#include<ctime>
using namespace std;

int main() { 
    const int MIN_VALUE = 1;
    const int MAX_VALUE = 6;

    int die1,die2;

    unsigned seed = time(0);
    srand(seed);

    die1 = (rand()%(MAX_VALUE - MIN_VALUE +1)) + MIN_VALUE;
    die2 = (rand()%(MAX_VALUE - MIN_VALUE +1)) + MIN_VALUE;

    while(die1 == die2); {
        die1 = (rand()%(MAX_VALUE - MIN_VALUE +1)) + MIN_VALUE;
        die2 = (rand()%(MAX_VALUE - MIN_VALUE +1)) + MIN_VALUE;

        cout<<"Value of die 1  is"<<die1<<endl;
        cout<<"Value of die 2 is" <<die2<<endl;
        cout<<endl;
    }
    return 0;
}

Answer 1

A couple of issues here:

• The ; at the end of line where the while statement begins means that the while is not connected to the block of code below. Remove it. (if die1 value equals die2 at the beginning itself, you will have an infinite loop there itself.)

• The condition to check is die1 != die2 because you want to roll the dice as long as they are not equal.

See Demo .

Answer 2

There are two mistakes in while(die1 == die2); .

The == makes the loop continue while the values are equal, but you want the opposite.
The condition could be endless if the two dice start off equal (because the rerolling never happens, see below).
Otherwise it will be "never".
The semicolon will prevent the while from having any effect on the following {} , it will be executed exactly once, in case the loop is not endless, otherwise never.

So change to:

while(die1 != die2)
{
    /* reroll */
}

In case you want to make your code easier to maintain and read, investigate about do {} while(); .