[英]Find weekly and weekend average sales of a month
I'm trying to compare average sales of a weekend and weekday in python.我试图在 python 中比较周末和工作日的平均销售额。
Suppose I have a dataset假设我有一个数据集
Order Date Units Sold day_week
2017-07-01 100 Sat
2017-07-02 100 Sun
2017-07-03 90 Mon
2017-07-04 90 Tue
2017-07-05 90 Wed
2017-07-06 90 Thu
2017-07-07 90 Fri
2017-07-08 80 Sat
2017-07-09 80 Sun
2017-07-10 100 Mon
2017-07-11 100 Tue
2017-07-12 100 Wed
2017-07-13 100 Thu
2017-07-14 100 Fri
I want to compare (average sales of weekend that is sat and sun) with (average sales of weekdays), but individually like (1st and 2nd with 3,4,5,6,7 sales) and (8,9 with 10,11,12,13,14)我想比较(周六和周日的周末平均销售额)与(工作日的平均销售额),但分别喜欢(第一和第二,3,4,5,6,7 销售额)和(8,9 和 10, 11,12,13,14)
So in 1st week, weekend average sales (100) will be more than weekday average sales(90) and in 2nd week , weekend average sales (80) will be less than weekday average sales (100)因此,在第一周,周末平均销售额 (100) 将高于工作日平均销售额 (90),而在第二周,周末平均销售额 (80) 将低于工作日平均销售额 (100)
Ok, here's assuming your data is in a DataFrame
format, but the date/time is simple str
(ie not datetime
):好的,这里假设您的数据采用DataFrame
格式,但日期/时间很简单str
(即不是datetime
):
import pandas as pd
# setting up part of your dataset
df = pd.DataFrame.from_dict({
'date':['2017-07-01','2017-07-02','2017-07-03','2017-07-04'],
'units_sold': [100,100,90,90],
'day_week': ['Sat','Sun','Mon','Tue']}
)
# defining a new column to help us, grouping by it and then summing:
df['is_weekend']=df['day_week'].apply(lambda x: x in {'Sat','Sun'})
df.groupby('is_weekend').mean()
Also, in the future, it's good conduct to write the code that generates your dataset (or a small part of it), otherwise the reader has to do it itself.此外,将来最好编写生成数据集(或其中一小部分)的代码,否则读者必须自己编写。
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