如何使用while循环在Python中打印范围内的第n个数字

Question

I'm working on a practice problem that says, "Use a "while" loop to print out every fifth number counting from 1 to 1000."

I can't seem to make it work.

This is what I've tried so far (as well as several small tweaks of this).

num = 1

while num in range(1, 1001):
    if num % 5 == 0:
        num += 1
print(num)

Thank you!

Answer 1

You're close. You want to print out every time the condition matches, but increment regardless of the condition.

num = 1

while num in range(1, 1001):
    if num % 5 == 0:
        print(num)  # print must be inside the condition
    num += 1  # the increase must be done on every iteration

Answer 2

for num in range(1, 1001):
    if num % 5 == 0:
        print(num)

You were pretty close, this should work.

@Wolf comment is also very helpful for you and relevant!

Answer 3

I would say Python style would be more like:

print(list(range(0, 1001, 5)[1:]))

Got you, yes then for while loop it looks like:

num = 1
while num < 1001:
    if not num % 5:
        print(num)
    num += 1