[英]Racket lang: access element in list
Give a single function to access the element a in the list L. 提供单个功能以访问列表L中的元素a。
(define L '(1 2 (a 3 4 5)))
Following the form (define id expr) which binds id to the result of expression I have tried the following: 按照将id绑定到表达式结果的形式(定义id expr),我尝试了以下操作:
(define L '(1 2 (a 3 4 5) (car(cdr L))))
cdr accesses the tail of the list, ie a 3 4 5, if I am not mistaken, and then I apply car on the tail to access the head of the list, ie a. cdr访问列表的末尾,即3 4 5,如果我没记错的话,然后我将car放在列表的末尾以访问列表的头,即a。 However, it is not working on DrRacket IDE.
但是,它在DrRacket IDE上不起作用。
I think you meant to do this: 我认为您打算这样做:
(define L '(1 2 (a 3 4 5)))
(car (car (cdr (cdr L))))
=> 'a
Which can also be written as: 也可以写成:
(caaddr L)
=> 'a
You included the (car(cdr L))
part inside the list L
. 您将
(car(cdr L))
部分包括在列表L
。
> (define L '(1 2 (a 3 4 5) (car(cdr L))))
> L
(list 1 2 (list 'a 3 4 5) (list 'car (list 'cdr 'L))) ;; oh no
But that still doesn't extract the 'a
because you need to access car
of the inner list: 但这仍然不能提取
'a
因为您需要访问内部列表的car
:
(define L '(1 2 (a 3 4 5)))
(car (car (cdr (cdr L))))
;; or (caaddr L)
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