使用Array.prototype.filter（）不会对数组重复数据删除

Question

I have the following data I'm trying to dedupe:

Actual

var data = [
  ['dupeValue', { data: 123 }],
  ['dupeValue', { data: 123 }],
  ['otherValue', { data: 1111111 }],
  ['dupeValue', { data: 123 }]
]

Expected

var data = [
  ['dupeValue', { data: 123 }],
  ['otherValue', { data: 1111111 }]
]

I tried the following, but doesn't work:

data.filter((value, i, arr) => {
  return value[0] !== arr[i][0]
})
// outputs []

What am I missing?

 var data = [ ['dupeValue', { data: 123 }], ['dupeValue', { data: 123 }], ['otherValue', { data: 1111111 }], ['dupeValue', { data: 123 }] ] var result = data.filter((value, i, arr) => { return value[0] !== arr[i][0] }) console.log(result) 

Answer 1

Your filter test is

var result = data.filter((value, i, arr) => {
  return value[0] !== arr[i][0]
});

But arr[i] will always refer to the current element being iterated over - the value , so no matter the input, value[0] !== arr[i][0] will always evaluate to false . (because value === arr[i] , so value[0] === arr[i][0] ).

You might add the value[0] to a Set , and when testing, check whether that value exists in the set yet or not:

 var data = [ ['dupeValue', { data: 123 }], ['dupeValue', { data: 123 }], ['otherValue', { data: 1111111 }], ['dupeValue', { data: 123 }] ] const firstElements = new Set(); var result = data.filter(([firstElement]) => { const alreadyHas = firstElements.has(firstElement); firstElements.add(firstElement); return !alreadyHas; }) console.log(result) 

Answer 2

You could use a reduce() to map to an object and Object.values() to get resultant array

 var data = [ ['dupeValue', { data: 123 }], ['dupeValue', { data: 123 }], ['otherValue', { data: 1111111 }], ['dupeValue', { data: 123 }] ] var result = Object.values(data.reduce((a, c) => (a[c[0]] = c, a), {})) console.log(result)