如何从c编程中的函数返回结构变量？

Question

I created a local structure student c inside the function, how to return student c from function to the the student d in the main fuction?

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
struct student
{
     char name[10];
}a,b;
struct student name(struct student *ptr)
{
    struct student c; 
    strcpy(c.name,ptr->name);
    return c.name;    //error
}
int main()
{
    printf("enter name");
    scanf("%c",&a.name);
    b.name=name (&a.name);   //error
    printf("%c",b.name);
    return 0;
}

Answer 1

Your question:

how to return struct variable from a function in c programming?

does not match your code.

In your code you try to return a single struct member (ie c.name ) but not the whole struct. Since the struct member is a char array (to be used as a string it seems) you get a lot of errors because i C you can't assign string variables (aka char array variables) using the = operator.

If you really wanted to return a struct simply do:

struct student name(struct student *ptr)
{
    struct student c; 
    strcpy(c.name,ptr->name);
    return c;    // Just use c instead of c.name;
}

and the call from main would be:

b = name(&a);

BTW:

scanf("%c",&a.name);

is wrong. I assume you want to read a word - not just a character - so %s is the specifier to use. Like: scanf("%9s", a.name);

Notice that scanf with %s only allows scan of 1 word. As a name can be several words you may want to use fgets instead.

This also applies to the printf , ie use %s instead of %c