如何使用Python / Regex替换/替换部分url和变量

Question

I'm trying to replace part of the following URL with string from a variable: https://somedomain.eu/api/one/some/2018/05/data How I can exclude some groups and use only one.

This is what I did:

def change(var_data):
  var = str(var_data) // for example: 11
  url = 'https://somedomain.eu/api/one/some/2018/05/data'
  url2 = re.sub(r'(\d\d)', var, url)
  print(url2)

The print looks like this: https://somedomain.eu/api/one/some/1111/11/data and it is wrong because I need to change only 05 to 11 , not 2018 to 1111

other version:

data_url_2 = re.sub(r'.+/(\d\d)/.+', month, data_url)
print(data_url_2)  

print = '11'

I was thinking of finding the way to make 3 groups and exclude first and the third one:

data_url_2 = re.sub(r'(.+/\d\d\d\d)(\d\d)(/.+)', month, data_url)

Answer 1

Probably doesn't need regex but let's do it anyway.

>>> import re

>>> url = 'https://somedomain.eu/api/one/some/2018/05/data'


>>> re.sub('/[\d]{2}/', '/11/', url)
'https://somedomain.eu/api/one/some/2018/11/data'


>>> re.sub('(?<=/)[\d]{2}(?=/)', '11', url)
'https://somedomain.eu/api/one/some/2018/11/data'

.

.

I was thinking of finding the way to make 3 groups and exclude first and the third one:

What?

Answer 2

One way without regex

def change(var_data):
  var = str(var_data)
  url = 'https://somedomain.eu/api/one/some/2018/05/data'
  url1 = url.split('/')
  url2 = '/'.join(url1[:-2] + [var] + [url1[-1]])
  print(url2)

change('11')
#https://somedomain.eu/api/one/some/2018/11/data