如何使用pandas iterrows（）获得当前迭代的计数？

Question

I am trying to iterate over a DataFrame , but the index , I get when looking through iterrows() is the index in the DataFrame. Instead, I want it to be 0 , 1 , 2 , 3 ...

        for ind, row in last_10.iterrows():
            print('ind', ind)

This returns:

2345
2346
2347
...

I want it to be:

0
1
2
...

Answer 1

Using enumerate

for ind, row in enumerate(last_10.iterrows()):
    print('ind', ind)
    print('data',row[1]['columns'])

---

range create

for ind in range(len(last_10)):
    print('ind', ind)
    print('data',df.iloc[ind]['columns'])

Answer 2

    from itertools import tee 


    import pandas as pd
    df = pd.DataFrame(['AA', 'BB', 'CC'], columns = ['value'])

    def pair_iterate(iter):
        first, second = tee(iter)
        next(second, None)
        return zip(first, second)

    for (i1, row1), (i2, row2) in pair_iterate(df.iterrows()):
        print(i1, i2, row1["value"], row2["value"])