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为什么我的重载转换运算符无法访问私有成员?

[英]Why does my overloaded casting operator not have access to private members?

I'm attempting to implement an overloaded casting operator on my templated array2d class using type T .我正在尝试使用类型T在我的模板化array2d类上实现重载的转换运算符。 So I'm to cast from array2d<T> to a new array2d<E> .所以我要从array2d<T>到一个新的array2d<E>

I'm able to perform the casting itself but problems arise when I try to set the casted data to the new instance of array2d<E> .我能够自己执行转换,但是当我尝试将转换数据设置为array2d<E>的新实例时出现问题。 The compiler tells me that the casting operator doesn't have access to the private members of array2d编译器告诉我,转换运算符无权访问array2d的私有成员

Here's where I am so far (edited out unrelated code for brevity)这是我到目前为止的位置(为简洁起见,编辑了不相关的代码)

array2d.h数组2d

template<typename T>
class array2d {
private:
    // Member Variables
    T** data;
    size_t width, height;
public:
    // constructors, methods, etc...

    // Cast Operator
    template<typename E>
    operator array2d<E>() const;
};

// Other overloaded operators...

// Overloaded Casting Operator
template<typename T>
template<typename E>
array2d<T>::operator array2d<E>() const{
    // Create new instance
    array2d<E> castedArr(width, height);
    // Allocate memory for the casted data, then cast each element
    E** newData = new E*[castedArr.get_height()];

    for (size_t i = 0; i < castedArr.get_height(); i++){
        newData[i] = new E[castedArr.get_width()];
        for (size_t j = 0; j < castedArr.get_width(); j++){
            newData[i][j] = (E)data[i][j];
        }
    }
    // issue here, can't set data because it's private.
    castedArr.data = newData;

    delete [] newData;
    newData = nullptr;

    return castedArr;
}

main.cpp主程序

#include "array2d.h"

int main(int argc, char *argv[]) {
// Cast Operator
    // Create an array2d<T> of
    // width = 5
    // height = 5
    // fill all elements with 42.1
    array2d<double> x(5, 5, 42.1);

    // Create a new array exactly the same as
    // x, where x is casted to int
    array2d<int> y = (array2d<int>) x;

    return 0;
}

This confused me as I have many other overloaded operators that can access the private members just fine using practically the exact same logic.这让我很困惑,因为我有许多其他重载运算符,它们可以使用几乎完全相同的逻辑访问私有成员。

Why does this happen and what can I do to rectify it?为什么会发生这种情况,我可以做些什么来纠正它?

When writing a template, you don't nail down the actual type, you create a blue print for different types.编写模板时,您无需确定实际类型,而是为不同类型创建蓝图。 array2d<double> and array2d<int> are different types, and by default, two instances of two different classes can't access their private members. array2d<double>array2d<int>是不同的类型,默认情况下,两个不同类的两个实例不能访问它们的私有成员。

You can fix that by declaring every instantiation of array2d a friend class of the template array2d :您可以通过将array2d的每个实例array2d模板array2d的友元类来解决这个array2d

template<typename T>
class array2d {
    /* ... */

    template<class E> friend class array2d;

    /* ... */
};

As a side note, I'm not quite sure wheter作为旁注,我不太确定是否

delete [] newData;

is a good idea.是个好主意。 You're destroying parts of the resources that the new array2d instance is supposed to manage.您正在破坏新的array2d实例应该管理的部分资源。 If you delete[] that again in array2d::~array2d() , you'll have undefined behavior.如果在array2d::~array2d()中再次delete[] ,则会出现未定义的行为。

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