根据其他列表中的值对列表中的列表进行排序

Question

I want to sort lists in a list based on values from another list. In the example the 5th order should be placed before 0 and 1 because the due date is earlier.

I already tried for loops and other sorting methods but the list in the list is not an integer, which makes ik too hard for me. Therefore I have no idea to solve the following:

orders = [[0, 1, 5], [2, 3 ,4]]
##due date for each order
duedates = [5000, 5000, 4500, 3000, 3000, 2750]

expected output: [[5,0,1], [4,3,2]]

Answer 1

Can you try the following:

>>> import numpy as np
>>> orders = np.array([[0, 1, 5], [2, 3 ,4]])
>>> duedates = np.array([5000, 5000, 4500, 3000, 3000, 2750])
>>> duedates = duedates.reshape(orders.shape)
>>> for i, j in zip(orders, duedates):
...   print([x for __, x in sorted(zip(j, i))])
...
[5, 0, 1]
[4, 2, 3]

Answer 2

for order in orders:
    orders_due = [duedates[i] for i in order]
    sorted_order = sorted(zip(order, orders_due), key=lambda x:x[1])
    print([i for (i,j) in sorted_order])