[英]How to set imageview resource from variable?
I have a lot of images (hundreds) and I need to put some of them as a resource of ImageView
, but if I would create If Then set Image to Image name, I die from these tons of code.我有很多图像(数百个),我需要将其中一些作为
ImageView
的资源,但是如果我创建 If Then 将 Image 设置为图像名称,我会死于这些大量的代码。 I want to set Image resource which name is inside a variable, but I can't find out how.我想设置名称在变量内的图像资源,但我不知道如何。 If I have
img.setImageResource(R.drawable.my_image);
如果我有
img.setImageResource(R.drawable.my_image);
How can I assign variable name at my_image
instead of true image name?如何在
my_image
分配变量名称而不是真实图像名称? Please help.请帮忙。 Thanks.
谢谢。
Try this:试试这个:
String resourceName = "clouds";
int resourceIdentifier = getResources().getIdentifier(resourceName, "drawable", Constants.CURRENT_CONTEXT.getPackageName());
Then然后
imgView.setImageResource(resourceIdentifier);
I don't know if I clearly understood your request but why don't you try to do that instead :我不知道我是否清楚地理解了您的要求,但您为什么不尝试这样做:
int my_image = R.id.my_image;
img.setImageResource(ContextCompat.getDrawable(this, my_image));
https://stackoverflow.com/a/29146895/8526518 for more informations about ContextCompat https://stackoverflow.com/a/29146895/8526518有关 ContextCompat 的更多信息
if you can prefer assets folder rather than resource, then you can try this code如果您更喜欢资产文件夹而不是资源,那么您可以尝试此代码
create sub-folder in assets directory.在资产目录中创建子文件夹。 use getAssets().list() for getting all file names from assets:
使用 getAssets().list() 从资产中获取所有文件名:
String[] images =getAssets().list("images");
ArrayList<String> listImages = new ArrayList<String>(Arrays.asList(images));
Now to set image in imageview you first need to get bitmap using image name from assets :现在要在 imageview 中设置图像,您首先需要使用 assets 中的图像名称获取位图:
InputStream inputstream=mContext.getAssets().open("images/"
+listImages.get(position));
Drawable drawable = Drawable.createFromStream(inputstream, null);
imageView.setImageDrawable(drawable);
just a convenient refactoring of the S-Sh answer if you use kotlin and like using its extensions functions:如果您使用 kotlin 并喜欢使用其扩展功能,则只是对 S-Sh 答案的方便重构:
fun ImageView.loadDrawableFromName(name:String, ctx: Context, visible:Int=View.VISIBLE){
val resId = ctx.resources.getIdentifier(name, "drawable", ctx.packageName)
this.setImageResource(resId)
this.visibility = visible
}
you can call it in both ways:您可以通过两种方式调用它:
imgname="IMGNAME"
myimageview.loadDrawableFromName(imgname, ctx)
and和
imgname="IMGNAME"
myimageview.loadDrawableFromName("@drawable/$imgname", ctx)
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