什么是 SQL 语法； 检查与您的 MariaDB 服务器版本相对应的手册？

Question

the code is totally true but during execute i face error

whats wrong with this code ... of course im beginner coder guys but help me please

THE ERROR IS :

You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near '52, v@test.com)VALUES ('niki','52','v@test.com')' at line 1

THE CODE IS :

<?php 
if(isset($_POST['submit'])){
   $Name= $_POST ['Name'];
   $Password = $_POST [ 'Password'];
  $Email= $_POST [ 'Email'];
   $connection = mysqli_connect('127.0.0.1','root','','loginapp');
   if($connection){
      echo "Hi Dude , we are conneted";
   }else{
      die('DataBase is Failed');
   }
   $query = "INSERT INTO `users`($Name , $Password, $Email)" ; 
   $query .= "VALUES ('$Name','$Password','$Email')";
  $result = mysqli_query($connection , $query);
  if (!$result){
     die('Query FAILED'. mysqli_error($connection));
  }
}else { 
   echo "Record Create"; 
}

Answer 1

You must use column names in place of variables in the insert statement.
Insted of
$query = "INSERT INTO users ($Name , $Password, $Email)" ; $query .= "VALUES ('$Name','$Password','$Email')"; ($Name , $Password, $Email)" ; $query .= "VALUES ('$Name','$Password','$Email')";

Use something like this

$query = "INSERT INTO users (Name , Password, Email)" ; $query .= "VALUES ('$Name','$Password','$Email')"; (Name , Password, Email)" ; $query .= "VALUES ('$Name','$Password','$Email')";