试图理解java中结合布尔和逻辑运算符的代码块

Question

Studying Java and this is a sample question I came across. I think I understand the logic behind the answer but could somebody confirm whether I am understanding it correctly?

public class Q8 {

    static boolean b1;
    static boolean b2;
    static boolean b3;

    public static void main(String[] args) {
        boolean trueOrFalse = (b1 = true) || (b2 = true) && (b3 = true); //Line 9
        System.out.println(b1 + ", " + b2 + ", " + b3);
    }
}   

Program prints true, false, false to console.

I understand that the class variables are assigned default values of false.

Am I right in saying that because b1 = true is assigning a value of true to b1 instead of testing for equality like the question is laid out to have you believe, the or operator shortcuts leaving b2 and b3 as their default values and that's why true, false, false prints to the console?

Answer 1

Yes, that is correct. You will set b1, evaluate and shortcut - so the rest is not set/evaluated.

Answer 2

(b1 = true) 将 true 分配给 b1，然后由于 OR 运算符 || 跳过其余部分，因此 b2 和 b3 保留其默认的 false 值

Answer 3

Basically your code is a little bit different then how you as a human would read it. The compilers makes a few lines from your one line.

// This is not exactly how it will be translated obviously, but this should make it a little bit more understandable for you.
if (trueOrFalse = (b1 = true))
else if (trueOrFalse = (b2 = true) && (b3 = true)); 

This means that b2 and b3 will always just be skipped

|| this is the OR operator and only checks the second statement when the first statement is false When ever one of the sides of an OR operator is true, code will execute.