[英]How to fetch results from user,post,comments tables in one query
The title may not be the fit to the question perfectly ! 标题可能不完全适合这个问题! pardon me
对不起
Goal 目标
I want to achieve the name
of the user
who has done a post
,the description
of that post( p_description
), the comments that are there on that post
,and the name of those who has provided comments ( comment_description
) 我要实现的
name
中的user
谁做了post
,将description
该职位(的p_description
),是那里的意见post
,如果谁提供意见的名称( comment_description
)
How can I achieve that ? 我怎样才能做到这一点?
I've three tables: 我有三张桌子:
user
post
and post
和
comments
User table is like : 用户表如下:
u_id
name
and so... u_id
name
等......
Post table, here it is : 邮政表,这里是:
u_id p_id
p_description
u_id
p_id
p_description
u_id
as foreign key from user
table , u_id
作为user
表的外键,
and the Comments
table is: 而
Comments
表是:
u_id
p_id
comment_description
. u_id
p_id
comment_description
。
note that the u_id and p_id in table comments are both as foreign keys from table user
and post
respectively. 请注意,表注释中的u_id和p_id分别是表
user
和post
外键。
I'm writing the following query for the above Goal : 我正在为上述目标编写以下查询:
SELECT p_description,f_name,comment_description as COMMENT FROM user JOIN post ON user.u_id = post.u_id JOIN comments ON user.u_id = comments.u_id
It gives me the post description
, name of that guy who has done post
, and the comments on that post
, and I want to have also the name of those guys who has done comments to that post. 它给了我
post description
,发post description
name of that guy who has done post
,以及the comments on that post
name of that guy who has done post
the comments on that post
,我想也有那些对那篇文章做过评论的人的名字 。
If the problem is not explained well. 如果问题没有得到很好的解释。
simply I want query for the above GOAL regarding those three tables. 我只想查询关于这三个表的上述目标 。
Join user
once more on the user ID in comments
. 在
comments
再次加入user
ID。
SELECT u1.name,
p1.p_description,
u2.name,
c1.comment_description
FROM user u1
INNER JOIN post p1
ON u1.u_id = p1.u_id
INNER JOIN comments c1
ON c1.p_id = p1.p_id
INNER JOIN user u2
ON u2.p_id = c1.p_id;
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