[英]SQL COUNT not working with nesting a SELECT query inside a LEFT outer join
I need a Count to work to use in my main select Original question Looking to add in a Count query with Group by INTO an existing working query 我需要一个Count才能在我的主选择中使用原始问题希望通过INTO现有的工作查询中的Group by添加一个Count查询
--- this join works ---
LEFT OUTER JOIN
WorkItemAssignedToUserFactvw AS IATUFact
ON
WI.WorkItemDimKey = IATUFact.WorkItemDimKey
AND IATUFact.DeletedDate IS NULL
--- this part below is in both queries ---
LEFT OUTER JOIN
UserDimvw AS AssignedToUser
ON
IATUFact.WorkItemAssignedToUser_UserDimKey = AssignedToUser.UserDimKey
LEFT OUTER JOIN
(
SELECT
WorkItemDimKey--,
DateKey,
--COUNT(WorkItemAssignedToUser_UserDimKey) AS Assignments
FROM
WorkItemAssignedToUserFactvw
WHERE
DeletedDate IS NULL
GROUP BY
WorkItemDimKey--,
--DateKey
)
IATUFact
ON WI.WorkItemDimKey = IATUFact.WorkItemDimKey
--- same query join as before except now it had an error
LEFT OUTER JOIN
UserDimvw AS AssignedToUser
ON
IATUFact.WorkItemAssignedToUser_UserDimKey = AssignedToUser.UserDimKey
Error: 错误:
Msg 207, Level 16, State 1, Line 292 Invalid column name 'WorkItemAssignedToUser_UserDimKey'.
消息207,级别16,状态1,行292无效的列名称'WorkItemAssignedToUser_UserDimKey'。
Use WorkItemAssignedToUser_UserDimKey
in your SELECT "should" fix this AND ADD to the group by .. 在您的SELECT中“使用”应该使用
WorkItemAssignedToUser_UserDimKey
来解决此问题,并将其添加到组中。
LEFT OUTER JOIN
(
SELECT
WorkItemAssignedToUser_UserDimKey,
WorkItemDimKey,
DateKey,
COUNT(WorkItemAssignedToUser_UserDimKey) AS Assignments
FROM
WorkItemAssignedToUserFactvw
WHERE
DeletedDate IS NULL
GROUP BY
WorkItemAssignedToUser_UserDimKey,
WorkItemDimKey,
DateKey
)
IATUFact
ON WI.WorkItemDimKey = IATUFact.WorkItemDimKey
--- same query join as before except now it had an error
LEFT OUTER JOIN
UserDimvw AS AssignedToUser
ON
IATUFact.WorkItemAssignedToUser_UserDimKey = AssignedToUser.UserDimKey
Maybe you had commented things out to see if they were the problem? 也许您已经注释掉了东西,看看是否是问题所在?
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.