我的 Main 函数只要求我输入 1 个。 如何获得将三个输入相乘的函数？

Question

What the program is trying to do is multiply 3 inputs (1.0f/3.0f) from 3 different functions to arrive at the volume of a pyramid. But I'm having trouble with the last function, which is asking me only for 1 input and therefore not multiplying the 3 inputs and (1.0f/3.0f).

float volume(float baselength, float baseWidth, float height){
    float frac = (1.0f/3.0f);
    float vol;
    vol = baselength*baseWidth*height*frac;
    return vol;
}
float main(){
    displayTitle();
    float num;

    printf("Enter a Number: ");
    scanf("%f", &num);

    float frac = (1.0f/3.0f);   
    float baselength;
    float baseWidth;
    float height;
    float result;

    result = volume(baselength, baseWidth, height);
    printf("The Volume of the Pyramid is %f",result);
}

I expect the output to be:

Welcome to the Pyramid Program
Enter a Number: 5 
Enter a Number: 4
Enter a Number: 3

The Volume of the Pyramid is 20.00

but the output is

Welcome to the Pyramid Program
Enter a Number: 5
The Volume of the Pyramid is 0.000000

Answer 1

This is because you are only reading one input.

scanf("%f", &num);

reads one input and stores it in the variable num, currently your baselength,basewidth and height are all initialised to 0 .You need to execute this three times for three inputs. I have modified your code

float volume(float baselength, float baseWidth, float height){
    float frac = (1.0f/3.0f);
    float vol;
    vol = baselength*baseWidth*height*frac;
    return vol;
}
int main(){
    //displayTitle();
    float num;
    float frac = (1.0f/3.0f);   
    float baselength;
    float baseWidth;
    float height;
    float result;

    printf("Enter a Number: ");
    scanf("%f", &baselength);
    printf("Enter a Number: ");
    scanf("%f", &baseWidth);
    printf("Enter a Number: ");
    scanf("%f", &height);


    result = volume(baselength, baseWidth, height);
    printf("The Volume of the Pyramid is %f",result);
    return 0;
}

Ps its always int main and it should always return 0