带分隔符的Bash脚本传递变量

Question

I am very new to bash scripting. I want to create a script that parses a variable that contains dashes and uses each parsed value to pass on to do additional function.

ex:

project="Acc-Account-Profile_info"
for i in ($project |sed 's/-/ /g')
do
    case $i in ($project |sed 's/-/ /g')
        echo DeptName = $i
        shift
        ;;
    case $i in ($project |sed 's/-/ /g')
        echo GroupName= = $i
        shift
        ;;
    case $i in ($project |sed 's/-/ /g')
        echo projectName= = $i
        shift
        ;;
    esac
done

I want the values to be like:-

DeptName = ACC
GroupName = Account
projectName= Profile_info

right now I keep getting syntax error. Any help would be greatly appreciated.

Answer 1

why don't you use read ?

project='Acc-Account-Profile_info'
IFS=- read -r DeptName GroupName projectName <<< "$project"
echo "DeptName = $DeptName"
echo "GroupName = $GroupName"
echo "projectName = $projectName"

Answer 2

IFS='-';set -f;project="Acc-Account-Profile_info"
for i in $project
{
case $i in
Account)
  GroupName=$i
  echo $GroupName;;
Acc) DeptName=$i
   echo $DeptName;;
Profile_info)
  projectName=$i
  echo $projectName;;
esac
}
unset IFS;set +f

better use set -- for more input data