[英]How To Write a 'GROUP BY' query to get all the Roles assigned to User for a given applicatoin
I have two tables User and User_Roles . 我有两个表User和User_Roles 。 A User can have multiple Roles.
一个用户可以具有多个角色。
USER TABLE 用户表
User_Id User_Name
1 Edward
2 John
3 Mark
USER_ROLES TABLE USER_ROLES表
User_ID Role
1 Admin
1 Writer
1 Form
2 Writer
3 Form
3 Writer
I want to write a query that gives me the following result 我想写一个查询,给我以下结果
User_ID User_Name Role
1 Edward Admin, Writer,Form
2 John Writer
3 Mark Form,Writer
I have tried using a GROUP BY
and I know this is how I can get the result but I am just not doing it right. 我尝试使用
GROUP BY
,但我知道这是如何获得结果的方法,但我做得不好。
SELECT COUNT(T0.[User_Id]),T0.[User_Name],T1.[Role]
FROM USER T0
INNER JOIN USER_ROLES T1 ON T0.User_ID = T1.User_ID
GROUP BY T0.[User_Name], T1.[Role]
I am using a COUNT
for test purpose only because when I do a GROUP BY
with an aggregate function , I get an error. 我将
COUNT
用于测试仅是因为当我使用聚合函数执行GROUP BY
时,会出现错误。
Use aggregation and STRING_AGG()
(available starting SQL Server 2017): 使用聚合和
STRING_AGG()
(从SQL Server 2017开始可用):
SELECT u.User_ID, u.User_Name, STRING_AGG(r.Role, ',') AS Roles
FROM user u
INNER JOIN user_roles r ON r.User_Id = u.User_Id
GROUP BY u.User_ID, u.User_Name
NB: you might want to order the aggregated strings so you do get predictable values, like: 注意:您可能想对聚合字符串进行排序,以便获得可预测的值,例如:
STRING_AGG(r.Role, ',') WITHIN GROUP (ORDER BY r.Role) AS Roles
An alternative is to us the FOR XML / STUFF trick : 对我们来说,另一种选择是FOR XML / STUFF技巧:
SELECT
U.USER_NAME,
STUFF((SELECT ',' + UR.ROLE
FROM [USER_ROLES] UR
WHERE UR.USER_ID = U.USER_ID
FOR XML PATH('')), 1, 1, '') [ROLES]
FROM [USER] U
GROUP BY U.USER_NAME, U.USER_ID
ORDER BY 1
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