我如何通过查询来命令，以便所有列的列等于true？

Question

So i have a model :

id = db.Column(db.Integer, primary_key=True) 
is_urgent = db.Column(db.Boolean, default=False)
creation_time = db.Column(db.DateTime, index=True, default=datetime.utcnow)

and i want to create a ordered list by a query so that all orders that are urgent go first and then all that arent urgent. And those two gropus are also ordered by creation time, so the first order of the query list would be the oldest urgent order and the most recent would be the not-urgent newest one,

can it be done with pure sqlalchemy ? or should i create a for loop after a simpler query ?

Answer 1

Query results can be ordered by using the order_by method on your query. This takes multiple arguments and your query will be sorted by each of these in turn. The desc method on each of the columns supplied to order_by can be used to control the direction of the sort. The following should work for you.

session.query(MyModel).order_by(MyModel.is_urgent.desc(), MyModel.creation_time)