如何根据条件对压缩列表进行排序？

Question

I'am trying to sort a zipped list based on the value. So the list is something like this

[('Job 1', '3', '1'), ('Job 2', '1', '3'), ('Job 3', '2', '3'),('Job 4', '4', '3')]

What I want to do is to sort the list based on the value of the index [1] and [2] . For example:

Job 1         3         1
Job 2         1         3
Job 3         2         3
Job 4         4         3

If the value in column 2 is smaller than column 3, the table would become:

Job 2         1         3
Job 3         2         3
Job 1         3         1
Job 4         4         3

I have been searching for the method but it seems like a dead end. So far what I found is just sort() the whole list based on the index.

Answer 1

You could just sort it by using the keyfunc that returns index 1 and index 2 item converted to int ,

>>> x
[('Job 1', '3', '1'), ('Job 2', '1', '3'), ('Job 3', '2', '3'), ('Job 4', '4', '3')]
>>> sorted(x, key=lambda x: (int(x[1]), int(x[2])))
[('Job 2', '1', '3'), ('Job 3', '2', '3'), ('Job 1', '3', '1'), ('Job 4', '4', '3')]
>>> y = _
>>> for i in x:
...   print(i)
... 
('Job 1', '3', '1')
('Job 2', '1', '3')
('Job 3', '2', '3')
('Job 4', '4', '3')
>>> for j in y:
...   print(j)
... 
('Job 2', '1', '3')
('Job 3', '2', '3')
('Job 1', '3', '1')
('Job 4', '4', '3')
>>>