[英]How to construct object from initializer list of pairs?
In this code I am trying to initialize class object using initializer_list of pair(int,pair(string,string)), but I am getting error in initializing class member map2 of type map(int,pair(string,string)). 在这段代码中,我尝试使用pair(int,pair(string,string))的initializer_list初始化类对象,但是我在初始化类型map(int,pair(string,string))的类成员map2时遇到错误。
Here is my code 这是我的代码
#include <iostream>
#include <string>
#include <initializer_list>
#include <map>
using namespace std;
class contact{
private:
map <int,pair<string,string>> map2;
public:
contact(initializer_list<pair<int,pair<string,string>>> m):map2(m){}
void display(){
for (const auto& it:map2){
cout<<it.first;
}
}
};
int main() {
contact obj{
make_pair(4,make_pair("parul","agrawal")),
make_pair(5,make_pair("keshav","agrawal")),
};
obj.display();
return 0;
}
Map elements have const
keys. Map元素具有const
键。
Change 更改
contact(initializer_list<pair<int, pair<string, string>>> m) : map2(m) {}
to 至
contact(initializer_list<pair<const int, pair<string, string>>> m) : map2(m) {}
On a side note, you could ditch make_pair()
too: 另外,你也可以抛弃make_pair()
:
contact obj
{
{4, {"parul", "agrawal"}},
{5, {"keshav", "agrawal"}},
};
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