如何在元组列表中访问元组的元素

Question

I am new to Python and doing some hands on.

I have a list of tuples of tuples (each tuple is having 3 sub-tuples) as below:

ABC = [   (('The', 'AT'), ('Fulton', 'NP-TL'), ('County', 'NN-TL')),   

(('Fulton', 'NP-TL'), ('County', 'NN-TL'), ('Grand', 'JJ-TL')), 

(('County', 'NN-TL'), ('Grand', 'JJ-TL'), ('Jury', 'NN-TL')), 

(('Grand', 'JJ-TL'), ('Jury', 'NN-TL'), ('said', 'VBD')), 

(('Jury', 'NN-TL'), ('said', 'VBD'), ('Friday', 'NR'))   ]

I need to extract the second value of sub-tuple in each tuple ie 3 values and get them in a Tuple , which will be added in list.

Please assist how to get this.

Expected result:

I need a new list derived from it as:

 ABC_subset = [('AT','NP-TL', 'NN-TL'),

('NP-TL','NN-TL', 'JJ-TL'),

('NN-TL','JJ-TL', 'NN-TL'),

('JJ-TL','NN-TL', 'VBD'),

('NN-TL','VBD', 'NR')] 

I am trying something like this:

 ABC_subset = [(t[1],u[1],v[1]) for tup in ABC for t,u,v in tup]

But it is not giving the expected answer.

Answer 1

[(x[1] for x in y) for y in your_list]

Answer 2

Let's say your first list is orig and the second list that you want is newlist . It can be done very simply with list comprehensions:

newlist = [tuple(j[1] for j in i) for i in orig]

Essentially, iterate through each row i of orig , and extract the second element from each tuple j in that row.

Answer 3

Use a List Comprehension like:

output = [tuple(j[1] for j in i) for i in inputlist]

You will need to convert the second expression to a tuple as else it would output a generator object