使用Ajax调用的wordpress PHP
[英]wordpress PHP with Ajax call
问题描述
Im looking to return user data back as a string through ajax with wordpress 
我正在寻找通过Wordpress通过Ajax将用户数据作为字符串返回的方式
Iv got the basic concept down iv把基本概念记下来
PHP 的PHP
this is placed in my functions.php
add_action('template_redirect', 'edit_user_concept'); function edit_user_concept(){ $id = $_POST['getbyID']; $user_info = get_userdata($id); echo 'Username: ' . $user_info->user_login . "\\n"; echo 'User roles: ' . implode(', ', $user_info->roles) . "\\n"; echo 'User ID: ' . $user_info->ID . "\\n"; }
Jquery/JS jQuery / JS
$.ajax({ url: "http://www.example.com/", method: "POST", data: { getbyID: "23", }, success: function(response){ console.log(response); //example script logic here } })
the console log result is correct how ever its also logging lots of html elements that are not included in this. 控制台日志结果是正确的，但是它还会记录许多未包含在其中的html元素。 Such as 如
im not exactly sure why. 我不完全清楚为什么。
here is a small example to large to post in its full 这是一个完整的小例子
Username: someusername User roles: subscriber User ID: 23 <!DOCTYPE html> <html lang="en-US"> <div id="loadtheme" class="loadtheme"></div> <head> etc etc etc....
Any thoughts? 有什么想法吗？
2 个解决方案
解决方案1
0 2019-04-08 11:26:03
Try exit or return after echo.I dont know the complete problem but hope this helps 回声后尝试退出或返回。我不知道完整的问题，但希望对您有所帮助
add_action('template_redirect', 'edit_user_concept');
function edit_user_concept(){
$id = $_POST['getbyID'];
$user_info = get_userdata($id);
echo 'Username: ' . $user_info->user_login . "\n".'User roles: ' . implode(', ', $user_info->roles) . "\n".'User ID: ' . $user_info->ID . "\n";
exit;
}
解决方案2
0 已采纳 2019-04-08 11:26:11
You are echoing the html without stopping it anywhere, you can use json response here, for json , first of all you need to use dataType: "json" in your ajax request as: 您正在回显html而不在任何地方停止它，您可以在此处使用json响应，对于json ，首先需要在ajax请求中使用dataType: "json" ：
url: "http://www.example.com/",
method: "POST",
dataType: "json" // need to use datatype here.
data: {
getbyID: "23",
}
Now, you need to store data in an array in your PHP as: 现在，您需要将数据存储在PHP中的array中，如下所示：
$result = array();
$result['Username'] = $user_info->user_login;
$result['User_roles'] = implode(', ', $user_info->roles);
$result['User_id'] = $user_info->ID;
Now, you can use json_encode() : 现在，您可以使用json_encode() ：
echo json_encode($result);
You can print json result as like: 您可以像这样打印json结果：
console.log(response.Username); // will print username
console.log(response.User_roles); // will print user roles
console.log(response.User_id); // will print user id
Complete Example: 完整的例子：
$.ajax({
url: "http://www.example.com/",
method: "POST",
dataType: "json" // json data type
data: {
getbyID: "23",
},
success: function(response){
console.log(response.Username);
console.log(response.User_roles);
console.log(response.User_id);
//example script logic here
}
});
PHP: PHP：
<?php
function edit_user_concept(){
$id = $_POST['getbyID'];
$user_info = get_userdata($id);
$result = array();
$result['Username'] = $user_info->user_login;
$result['User_roles'] = implode(', ', $user_info->roles);
$result['User_id'] = $user_info->ID;
echo json_encode($result); // will return json response
}
?>
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