[英]Vector in the initializer list of a class
I have a learner list/vector defined in one .hpp
file like this: 我在一个
.hpp
文件中定义了一个学习者列表/向量,如下所示:
std::vector<DecisionTree> learners_;
. 。
Now in the constructor, this is used like this: 现在在构造函数中,它的用法如下:
Bagging::Bagging(const DataReader& dr, const int ensembleSize, uint seed) :
dr_(dr),
ensembleSize_(ensembleSize),
learners_({}) {
random_number_generator.seed(seed);
buildBag();
}
What is happening in the constructor? 构造函数中发生了什么?
Does the program try to fill only two instances within that vector where the first one is a random number and second one is a call to a function? 程序是否只尝试填充该向量中的两个实例,其中第一个是随机数,第二个是对函数的调用? But how does it work because
buildBag
returns a decision tree but the second argument returns an integer and we declared it as a vector of decisionTrees? 但是它如何工作,因为
buildBag
返回一个决策树,而第二个参数返回一个整数,我们将其声明为buildBag
的向量?
Why are there curly brackets ({})
? 为什么会有大括号
({})
?
As I have always programmed in java and python, this is hard to grasp and it does not come from any book but from the code example. 正如我一直使用Java和python编程一样,这很难理解,它不是来自任何书籍,而是来自代码示例。
dr_(dr), ensembleSize_(ensembleSize), learners_({})
: These are used to initialize the object variables of Bagging
Class to the specific values provided when the constructor is called. dr_(dr), ensembleSize_(ensembleSize), learners_({})
:它们用于将Bagging
Class的对象变量初始化为调用构造函数时提供的特定值。
({})
means that the std::vector<DecisionTree> learners_
is initialized to just an empty vector through an initializer list (it's a C++11 thing). ({})
意味着通过初始化列表将std::vector<DecisionTree> learners_
初始化为一个空向量(这是C ++ 11的事情)。
{
random_number_generator.seed(seed);
buildBag();
}
Finally, these statements are the body of the constructor of Bagging
Class. 最后,这些语句是
Bagging
类的构造函数的主体。 Plain commands that are executed upon creation of an object. 创建对象时执行的普通命令。
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