[英]BLOB to XMLType XML parsing failed in oracle
I can't convert BLOB to XMLType in oracle database. 我无法在Oracle数据库中将BLOB转换为XMLType。 I've tried this:
我已经试过了:
select
XMLType( BLOB_COLUMN,
1 /* this is character set ID. 1 == USASCII | ISO-8859-2 char ID?*/
) as XML
from my_table;
I got this error message: 我收到此错误消息:
ORA-31011: XML parsing failed
ORA-19202: Error occurred in XML processing
LPX-00200: could not convert from encoding US-ASCII to ISO-8859-2
Error at line 1
ORA-06512: at "SYS.XMLTYPE", line 265
ORA-06512: at line 1
31011. 00000 - "XML parsing failed"
*Cause: XML parser returned an error while trying to parse the document.
*Action: Check if the document to be parsed is valid.
My question is, how to convert this BLOB (ISO-8859-2) to XMLType? 我的问题是,如何将此BLOB(ISO-8859-2)转换为XMLType? What is the character ID of ISO-8859-2?
ISO-8859-2的字符ID是什么?
Thanks. 谢谢。
Use nls_charset_id to get ID: 使用nls_charset_id获取ID:
select
XMLType( BLOB_COLUMN,
nls_charset_id('ISO-8859-2')
) as XML
from my_table;
NLS_CHARSET_ID returns the character set ID number corresponding to character set name string.
NLS_CHARSET_ID返回与字符集名称字符串相对应的字符集ID号。
You can get the character set ID with nls_charset_id
function. 您可以使用
nls_charset_id
函数获取字符集ID。
Try this: 尝试这个:
select
XMLType( BLOB_COLUMN,
nls_charset_id('EE8ISO8859P2')
) as XML
from my_table;
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