选择并遍历两个目录linux中的差异

Question

I have bash script that that loops through files in the raw folder and puts them into the audio folder. This works just fine.

#!/bin/bash
PATH_IN=('/nas/data/customers/test2/raw/')
PATH_OUT=('/nas/data/customers/test2/audio/')

mkdir -p /nas/data/customers/test2/audio
IFS=$'\n'
find $PATH_IN -type f -name '*.wav' -exec basename {} \; | while read -r file; do
    sox -S ${PATH_IN}${file} -e signed-integer ${PATH_OUT}${file}
done

My issue is that, as the folders grow I do not want to run the script on the files that has already been converted, so I would like to loop over only the files that has not been converted yet. Ie the files only in raw but not in audio.

I found the function

diff audio raw

That can I do just that, but I cannot find a good way to incorporate this into my bash script. Any help or nudges in the right direction would be highly appreciated.

Answer 1

You could do:

diff <(ls -1a $PATH_OUT) <(ls -1a $PATH_IN) | grep -E ">" | sed -E 's/> //'

The first part will diff the files on both folders, the second part will filter out to get only the additions, and the third one will clean the list from the diff symbols to get just the names.