如何创建一个字典，其中包含文本中的单词作为键和“它出现的子列表”作为值？

Question

My question is quite similar to others but here my list is kind of special.

I have to create a search engine in Python. For that, I have to create a dictionary as I said in the title.

Let me give you the context:

I have basically a text which is made of several parts separated by "[==========]".

Like :

  [blablabla][blabliblou]
  [==========]
  [blablablou][blibloubla]
  [=========]
  [oubabababa][baboulila]

I created an algorithm that combine these lists until we "hit" a "=========="and put them into a single list where [blablabla blabliblou] is list[O], [blablablou][blibloubla] is list[1] etc...

The algorithm :

  import re
  file = open("mytext.txt","r",encoding="utf-8")
  list = []
  dico = {}
  d = file.read()

  x = re.split(r"=+", d)
  for i in range(len(x)):
  liste.append(x[i])

I have an output like :

  [ [blablabla blabliblou] [blablablou blibloubla] [oubabababa baboulila] ]

But now the second step is to create a dictionary that has all the words of the text as key and the sublist(s) that contain them as value(s).

I tried to use a conditional loop as the following :

  import re
  file = open("mytext.txt","r",encoding="utf-8")
  list = []
  numd = 0
  dico = {}
  d = file.read()

  for x in file:
  x = re.split(r"=+", d)
     for i in range(len(x)):
     list.append(x[i])
     numd =+ 1
        for word in list:
           if word in dico:
               if numd not in dico[word]:
                  dico[word].append(numd)
           else:
              dico[word] = [numd]

The expected output is :

    {blablabla:1, blablilou:1, blablablou:2, blibloubla:2, oubabababa:3,
baboulila:3}

but my list is still empty.

Thank you in advance for your reply! I would be so grateful

Answer 1

How about this?

from collections import defaultdict
all_dict = defaultdict(list)
for index, val in enumerate(x):
    for value in val:
        if value not in all_dict:
            all_dict[value].append(index)

print(all_dict)

It will get you the expected output:

defaultdict(list,
            {'blablabla': [0],
             'blabliblou': [0],
             'blablablou': [1],
             'blibloubla': [1],
             'oubabababa': [2],
             'baboulila': [2]})

Answer 2

from collections import defaultdict

l = [ ["blablabla", "blabliblou"], ["blablablou", "blibloubla"], ["oubabababa", "baboulila"] ]

d = defaultdict(list)
for i, line in enumerate(l):
    [d[word].append(i) for word in line]

print(dict(d))
>>> {'blablabla': [0], 'oubabababa': [2], 'blablablou': [1], 'blabliblou': [0], 'baboulila': [2], 'blibloubla': [1]}

Answer 3

This is the code that I have so far :

  import re 
  from collections import defaultdict 
  file = open("mytext.txt","r",encoding="utf-8") 
  l = [] 
  d = file.read() 

  x = re.split(r"=+", d) 
  for i in range(len(x)): 
     l.append(x[i]) 

  d = defaultdict(list) 
 for i, line in enumerate(l): 
    [d[word].append(i) for word in line]

It seems to work but the keys are the letters and the values are the sublists where the letter occur