[英]Java generics with parameter - inheritance
I have the following code: 我有以下代码:
public class Inheritance {
class A<T,U,V>{
}
class B<T,U,V> extends A<T,U,T>{
}
}
Could somebody explain me, how it actually works? 有人可以解释一下,它究竟是如何运作的? Does the Class B extend only A class, which parameters are "T,U,T", or it extends the actual A"T,U,V" class? B类是否只扩展A类,参数是“T,U,T”,还是扩展了实际的A“T,U,V”类?
A
's T
= B
's T
A
的T
= B
的T
A
's U
= B
's U
A
的U
= B
的U
A
's V
= B
's T
A
的V
= B
的T
B<String, Integer, Void> b = null;
A<String, Integer, String> a = b;
Does the Class B extend only A class, which parameters are "T,U,T" B类是否只扩展A类,参数为“T,U,T”
Yes, exactly. 对,就是这样。
or it extends the actual A"T,U,V" class? 或者它扩展了实际的A“T,U,V”类?
It's a template, there are no actual generic parameters. 它是一个模板,没有实际的通用参数。 It's a way to match your own parameter types with the parent's ones. 这是一种匹配您自己的参数类型与父类参数类型的方法。 If there is a B<String, Integer, Long>
instance, there will be a parent object A<String, Integer, String>
backing it. 如果有一个B<String, Integer, Long>
实例,则会有一个父对象A<String, Integer, String>
支持它。
Let put it into real example: 让我们把它放到真实的例子中:
public class Inheritance {
public static class A<T,U,V>{
T t;
U u;
V v;
A(T t, U u, V v) {
this.t = t;
this.u = u;
this.v = v;
}
T getT() {return t;}
U getU() {return u;}
V getV() {return v;}
}
public static class B<T,U,V> extends A<T,U,T>{
public B(T t, U u, V v) {
super(t, u ,t);
}
}
public static void main(String[] args) {
B<Boolean, Integer, String> b = new B<>(false, 1, "string");
// 't' attribute is Boolean
// since type parameter T of class B is Boolean
Boolean t = b.getT();
// 'v' attribute is Boolean
// since type parameters T and V of class A must have the same type as
// type parameter T of class B
Boolean v = b.getV();
}
}
Basically class B extends class A (which has three generic params). 基本上B类扩展了A类(它有三个通用参数)。 By declaring B<T,U,V> extends A<T,U,T>
you just bind the A's first and A's third generic param to the same type of B's first param 通过声明B<T,U,V> extends A<T,U,T>
你只需将A的第一个和第三个通用参数绑定到同一类型的B的第一个参数上
As shown in example in constructor of class B we have three distinct types - Boolean, Integer, String, but in constructor of class A we have only two distinct types Boolean, Integer because 1st and 3th constructor param of class A are both bound to Boolean type 如类B的构造函数中的示例所示,我们有三种不同的类型 - Boolean,Integer,String,但是在类A的构造函数中,我们只有两个不同的类型Boolean,Integer因为类A的第1和第3个构造函数参数都绑定到Boolean类型
More on generics and inheritence can be found here: https://docs.oracle.com/javase/tutorial/java/generics/inheritance.html 有关泛型和继承的更多信息,请访问: https : //docs.oracle.com/javase/tutorial/java/generics/inheritance.html
In this code, the templated type " identifiers " for each class are not linked to each other, let me modify the snippet to explain what I mean : 在这段代码中,每个类的模板化类型“ 标识符 ”没有相互链接,让我修改片段来解释我的意思:
public class Inheritance {
class A<T,U,V> { }
class B<I,J,K> extends A<I,J,I>{ }
}
The code is the same as before. 代码与以前相同。 You can see that there is no "naming" correlation between I,J,K and T,U,V. 您可以看到I,J,K和T,U,V之间没有“命名”关联。
Here the types I and J are forwarded to A. From A's perspective, a substitution is made with : T=I, U=J, V=I. 这里,类型I和J被转发到A.从A的角度来看,替换是:T = I,U = J,V = I.
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.