[英]How to get int from char in C
(i'm french, sorry for my bad english) (我是法国人,对不起我的英语不好)
I don't know how to get an int from a char[], the patern of the char will be the same everytime : "prendre 2", "prendre 44", "prendre 710"... 我不知道如何从char []获得一个int,每次的char模式都相同:“ prendre 2”,“ prendre 44”,“ prendre 710” ...
I want to check if the pattern of the sentence is correct and get the integer. 我想检查句子的模式是否正确并获取整数。
I have try to do this, but as you see, the problem is i just can check if the integer is between 0-9 because I check only one char. 我已经尝试执行此操作,但是如您所见,问题是我只能检查整数是否在0-9之间,因为我只检查了一个字符。
[...]
else if (est_prendre(commande)){
/* if the output is 1*/
int number = commande[8]- '0'
}
int est_prendre(char *commande){
int i;
char temp[9] = "";
char c = commande[8];
int num = c - '0';
for (i=0; i<8; i++){
temp[i] = commande[i];
}
if (strcmp ("prendre ", temp) == 0)
{
if ( /* num IS INTEGER? */)
{
return 1;
}
else
{
return 0;
}
} else {
return 0;
}
}
I expect if commande = "prendre 3", output of est_prendre is 1 because the pattern is correct And after than to put the integer into the variable number. 我期望如果commande =“ prendre 3”,则est_prendre的输出为1,因为模式正确,然后将整数放入变量号中。
Thank You! 谢谢!
This is very basic, you should (re)read any reference/tutorial on C that you have used to learn the language. 这是非常基础的,您应该(重新)阅读用于学习该语言的任何有关C的参考/教程。
You should just use the sscanf()
standard function: 您应该只使用
sscanf()
标准函数:
int value;
if (sscanf(commande, "prendre %d", &value) == 1)
{
... it was a match, the variable 'value' will be set to the number from the string
}
you can delete the (strange-looking) code that copies characters from commande
to temp
, and the temp
variable too of course. 您可以删除将字符从
commande
复制到temp
的(看起来很奇怪)代码,当然也删除temp
变量。 Just inspect the commande
string directly. 只需直接检查
commande
字符串即可。
Assuming that 'commande + 8' is a valid substring, what you need is atoi() function (ASCII to Integer). 假设“ commande + 8”是有效的子字符串,那么您需要的是atoi()函数(ASCII到Integer)。 This function is widely documented, and you can easily find online its usage.
此功能已被广泛记录,您可以在网上轻松找到其用法。
int number = atoi(commande+8);
Just remember that the substring terminates at the first non-digit character: 请记住,子字符串在第一个非数字字符处终止:
Note: atoi converts input string into integer, and you can use it if you are sure it fits expected input. 注意:atoi将输入字符串转换为整数,如果确定它适合预期的输入,则可以使用它。 So, if you expect to have either long integers or float values in your string you can use atol() (ASCII to long) or atof() (ASCII to float).
因此,如果您希望字符串中包含长整数或浮点值,则可以使用atol()(ASCII转换为long)或atof()(ASCII转换为浮点)。
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