在 C# 中使用秒表
[英]Using Stopwatch in C#
问题描述
Does anyone know how I can add a timer function to this code that solves sudoku puzzles?
有谁知道我如何向这段解决数独谜题的代码添加计时器功能？ I've tried the Stopwatch class but I can't get it to work because I don't know exactly where to put it.我试过 Stopwatch 类，但我无法让它工作，因为我不知道该把它放在哪里。 I've tried several places but always get errors.我试过几个地方，但总是出错。 The main purpose of the code works but I'd like to add a timer function to see how long the code ran for.该代码的主要目的是有效的，但我想添加一个计时器函数来查看代码运行了多长时间。
using System;
namespace SuDoKu
{
public class SuDoKu
{
private int[,] grid;
public SuDoKu()
{
grid = new int[9, 9];
}
static void Main(string[] args)
{
SuDoKu sdk = new SuDoKu();
int[,] grd = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 } };
for(int i = 0; i < 9; i++)
for(int j = 0; j < 9; j++)
sdk.EnterToGrid(grd[i, j], new Point(i, j));
Console.WriteLine("Original Grid");
sdk.Display();
sdk.Solve(sdk.NextAvailableCell(), new Point());
Console.WriteLine("\n\n\nSolved Grid");
sdk.Display();
Console.WriteLine();
}
public void Display()
{
for(int i = 0; i < 9; i++)
{
Console.WriteLine();
for(int j = 0; j < 9; j++)
{
if(ShowFromGrid(new Point(i, j)) == 0) {
Console.Write("0 ");
}
else
{
Console.Write(ShowFromGrid(new Point(i, j)) + " ");
}
if(j == 2 || j == 5)
{
Console.Write("| ");
}
}
if(i == 2 || i == 5) {
Console.Write("\n------|-------|------ ");
}
}
}
public void EnterToGrid(int num, Point pos) {
grid[pos.X, pos.Y] = num;
}
public int ShowFromGrid(Point pos) {
return grid[pos.X, pos.Y];
}
public void Solve(Point pos, Point prevPos) {
if(pos.X < 9 && pos.Y < 9)
{
Point posPrev = new Point();
if(grid[pos.X, pos.Y] == 0)
{
for(int i = 1; i <= 9; i++)
{
if(IsThisNumberPossibleInTheGrid(i, pos))
{
grid[pos.X, pos.Y] = i;
posPrev.X = pos.X;
posPrev.Y = pos.Y;
Point posNext = NextAvailableCell();
if(!posNext.Equals(new Point()))
Solve(posNext, posPrev);
}
}
if(grid[pos.X, pos.Y] == 0)
{
if(!prevPos.Equals(new Point()))
grid[prevPos.X, prevPos.Y] = 0;
return;
}
}
}
else
{
Point posNext = NextAvailableCell();
if(!posNext.Equals(new Point()))
Solve(posNext, pos);
}
}
public Point NextAvailableCell()
{
for(int i = 0; i < 9; i++)
for(int j = 0; j < 9; j++)
if(grid[i, j] == 0)
return new Point(i, j);
return new Point();
}
public bool IsThisNumberPossibleInTheGrid(int num, Point pos) {
if(IsThisNumberPossibleInTheBlock(num, pos))
{
for(int i = 0; i < 9; i++)
{
if(grid[i, pos.Y] == num && pos.X != i)
{
return false;
}
if(grid[pos.X, i] == num && pos.Y != i)
{
return false;
}
}
return true;
}
return false;
}
public bool IsThisNumberPossibleInTheBlock(int num, Point pos)
{
Point Grid = new Point();
Grid.X = (pos.X >= 0 && pos.X <= 2) ? 0 : ((pos.X >= 3 && pos.X <= 5) ? 3 : ((pos.X >= 6 && pos.X <= 8) ? 6 : -1));
Grid.Y = (pos.Y >= 0 && pos.Y <= 2) ? 0 : ((pos.Y >= 3 && pos.Y <= 5) ? 3 : ((pos.Y >= 6 && pos.Y <= 8) ? 6 : -1));
if(!Grid.Equals(new Point()))
{
for(int i = Grid.X; i < Grid.X + 3; i++)
{
for(int j = Grid.Y; j < Grid.Y + 3; j++)
{
if(grid[i, j] == num && !pos.Equals(new Point(i, j)))
return false;
}
}
return true;
}
return false;
}
}
public class Point
{
public int X;
public int Y;
public Point()
{
this.X = -1;
this.Y = -1;
}
public Point(int x, int y)
{
this.X = x;
this.Y = y;
}
public bool Equals(Point p)
{
return (this.X == p.X && this.Y == p.Y) ? true : false;
}
}
}
3 个解决方案
解决方案1
39 已采纳 2019-04-15 12:14:04
Does anyone know how I can add a timer function to this code that solves sudoku puzzles?有谁知道我如何向这个解决数独谜题的代码添加一个计时器功能？ I've tried the Stopwatch class but I can't get it to work because I don't know exactly where to put it.我试过秒表课，但我无法让它工作，因为我不知道把它放在哪里。 I've tried several places but always get errors.我试过好几个地方，但总是出错。 The main purpose of the code works but I'd like to add a timer function to see how long the code ran for.代码的主要目的有效，但我想添加一个计时器功能来查看代码运行了多长时间。
using System;
namespace SuDoKu
{
public class SuDoKu
{
private int[,] grid;
public SuDoKu()
{
grid = new int[9, 9];
}
static void Main(string[] args)
{
SuDoKu sdk = new SuDoKu();
int[,] grd = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 } };
for(int i = 0; i < 9; i++)
for(int j = 0; j < 9; j++)
sdk.EnterToGrid(grd[i, j], new Point(i, j));
Console.WriteLine("Original Grid");
sdk.Display();
sdk.Solve(sdk.NextAvailableCell(), new Point());
Console.WriteLine("\n\n\nSolved Grid");
sdk.Display();
Console.WriteLine();
}
public void Display()
{
for(int i = 0; i < 9; i++)
{
Console.WriteLine();
for(int j = 0; j < 9; j++)
{
if(ShowFromGrid(new Point(i, j)) == 0) {
Console.Write("0 ");
}
else
{
Console.Write(ShowFromGrid(new Point(i, j)) + " ");
}
if(j == 2 || j == 5)
{
Console.Write("| ");
}
}
if(i == 2 || i == 5) {
Console.Write("\n------|-------|------ ");
}
}
}
public void EnterToGrid(int num, Point pos) {
grid[pos.X, pos.Y] = num;
}
public int ShowFromGrid(Point pos) {
return grid[pos.X, pos.Y];
}
public void Solve(Point pos, Point prevPos) {
if(pos.X < 9 && pos.Y < 9)
{
Point posPrev = new Point();
if(grid[pos.X, pos.Y] == 0)
{
for(int i = 1; i <= 9; i++)
{
if(IsThisNumberPossibleInTheGrid(i, pos))
{
grid[pos.X, pos.Y] = i;
posPrev.X = pos.X;
posPrev.Y = pos.Y;
Point posNext = NextAvailableCell();
if(!posNext.Equals(new Point()))
Solve(posNext, posPrev);
}
}
if(grid[pos.X, pos.Y] == 0)
{
if(!prevPos.Equals(new Point()))
grid[prevPos.X, prevPos.Y] = 0;
return;
}
}
}
else
{
Point posNext = NextAvailableCell();
if(!posNext.Equals(new Point()))
Solve(posNext, pos);
}
}
public Point NextAvailableCell()
{
for(int i = 0; i < 9; i++)
for(int j = 0; j < 9; j++)
if(grid[i, j] == 0)
return new Point(i, j);
return new Point();
}
public bool IsThisNumberPossibleInTheGrid(int num, Point pos) {
if(IsThisNumberPossibleInTheBlock(num, pos))
{
for(int i = 0; i < 9; i++)
{
if(grid[i, pos.Y] == num && pos.X != i)
{
return false;
}
if(grid[pos.X, i] == num && pos.Y != i)
{
return false;
}
}
return true;
}
return false;
}
public bool IsThisNumberPossibleInTheBlock(int num, Point pos)
{
Point Grid = new Point();
Grid.X = (pos.X >= 0 && pos.X <= 2) ? 0 : ((pos.X >= 3 && pos.X <= 5) ? 3 : ((pos.X >= 6 && pos.X <= 8) ? 6 : -1));
Grid.Y = (pos.Y >= 0 && pos.Y <= 2) ? 0 : ((pos.Y >= 3 && pos.Y <= 5) ? 3 : ((pos.Y >= 6 && pos.Y <= 8) ? 6 : -1));
if(!Grid.Equals(new Point()))
{
for(int i = Grid.X; i < Grid.X + 3; i++)
{
for(int j = Grid.Y; j < Grid.Y + 3; j++)
{
if(grid[i, j] == num && !pos.Equals(new Point(i, j)))
return false;
}
}
return true;
}
return false;
}
}
public class Point
{
public int X;
public int Y;
public Point()
{
this.X = -1;
this.Y = -1;
}
public Point(int x, int y)
{
this.X = x;
this.Y = y;
}
public bool Equals(Point p)
{
return (this.X == p.X && this.Y == p.Y) ? true : false;
}
}
}
解决方案2
2 2019-04-15 12:09:15
Does anyone know how I can add a timer function to this code that solves sudoku puzzles?有谁知道我如何向这个解决数独谜题的代码添加一个计时器功能？ I've tried the Stopwatch class but I can't get it to work because I don't know exactly where to put it.我试过秒表课，但我无法让它工作，因为我不知道把它放在哪里。 I've tried several places but always get errors.我试过好几个地方，但总是出错。 The main purpose of the code works but I'd like to add a timer function to see how long the code ran for.代码的主要目的有效，但我想添加一个计时器功能来查看代码运行了多长时间。
using System;
namespace SuDoKu
{
public class SuDoKu
{
private int[,] grid;
public SuDoKu()
{
grid = new int[9, 9];
}
static void Main(string[] args)
{
SuDoKu sdk = new SuDoKu();
int[,] grd = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0 } };
for(int i = 0; i < 9; i++)
for(int j = 0; j < 9; j++)
sdk.EnterToGrid(grd[i, j], new Point(i, j));
Console.WriteLine("Original Grid");
sdk.Display();
sdk.Solve(sdk.NextAvailableCell(), new Point());
Console.WriteLine("\n\n\nSolved Grid");
sdk.Display();
Console.WriteLine();
}
public void Display()
{
for(int i = 0; i < 9; i++)
{
Console.WriteLine();
for(int j = 0; j < 9; j++)
{
if(ShowFromGrid(new Point(i, j)) == 0) {
Console.Write("0 ");
}
else
{
Console.Write(ShowFromGrid(new Point(i, j)) + " ");
}
if(j == 2 || j == 5)
{
Console.Write("| ");
}
}
if(i == 2 || i == 5) {
Console.Write("\n------|-------|------ ");
}
}
}
public void EnterToGrid(int num, Point pos) {
grid[pos.X, pos.Y] = num;
}
public int ShowFromGrid(Point pos) {
return grid[pos.X, pos.Y];
}
public void Solve(Point pos, Point prevPos) {
if(pos.X < 9 && pos.Y < 9)
{
Point posPrev = new Point();
if(grid[pos.X, pos.Y] == 0)
{
for(int i = 1; i <= 9; i++)
{
if(IsThisNumberPossibleInTheGrid(i, pos))
{
grid[pos.X, pos.Y] = i;
posPrev.X = pos.X;
posPrev.Y = pos.Y;
Point posNext = NextAvailableCell();
if(!posNext.Equals(new Point()))
Solve(posNext, posPrev);
}
}
if(grid[pos.X, pos.Y] == 0)
{
if(!prevPos.Equals(new Point()))
grid[prevPos.X, prevPos.Y] = 0;
return;
}
}
}
else
{
Point posNext = NextAvailableCell();
if(!posNext.Equals(new Point()))
Solve(posNext, pos);
}
}
public Point NextAvailableCell()
{
for(int i = 0; i < 9; i++)
for(int j = 0; j < 9; j++)
if(grid[i, j] == 0)
return new Point(i, j);
return new Point();
}
public bool IsThisNumberPossibleInTheGrid(int num, Point pos) {
if(IsThisNumberPossibleInTheBlock(num, pos))
{
for(int i = 0; i < 9; i++)
{
if(grid[i, pos.Y] == num && pos.X != i)
{
return false;
}
if(grid[pos.X, i] == num && pos.Y != i)
{
return false;
}
}
return true;
}
return false;
}
public bool IsThisNumberPossibleInTheBlock(int num, Point pos)
{
Point Grid = new Point();
Grid.X = (pos.X >= 0 && pos.X <= 2) ? 0 : ((pos.X >= 3 && pos.X <= 5) ? 3 : ((pos.X >= 6 && pos.X <= 8) ? 6 : -1));
Grid.Y = (pos.Y >= 0 && pos.Y <= 2) ? 0 : ((pos.Y >= 3 && pos.Y <= 5) ? 3 : ((pos.Y >= 6 && pos.Y <= 8) ? 6 : -1));
if(!Grid.Equals(new Point()))
{
for(int i = Grid.X; i < Grid.X + 3; i++)
{
for(int j = Grid.Y; j < Grid.Y + 3; j++)
{
if(grid[i, j] == num && !pos.Equals(new Point(i, j)))
return false;
}
}
return true;
}
return false;
}
}
public class Point
{
public int X;
public int Y;
public Point()
{
this.X = -1;
this.Y = -1;
}
public Point(int x, int y)
{
this.X = x;
this.Y = y;
}
public bool Equals(Point p)
{
return (this.X == p.X && this.Y == p.Y) ? true : false;
}
}
}
解决方案3
1 2022-12-15 07:23:07
In .NET 7.0 there were some improvements in the Stopwatch class.在.NET 7.0中， Stopwatch类有一些改进。 There is a better way to use Stopwatch that will be more accurate, slightly faster, and won't use memory allocation at all!有一种更好的使用Stopwatch的方法，它会更准确、速度稍快，而且根本不会使用内存分配！
You should use the methods Stopwatch.GetTimeStamp() & Stopwatch.GetElapsedTime(long) to make the improvements.您应该使用Stopwatch.GetTimeStamp()和Stopwatch.GetElapsedTime(long)方法进行改进。
An example would be:一个例子是：
long startTime = Stopwatch.GetTimestamp();
// Do Something...
TimeSpan elapsedTime = Stopwatch.GetElapsedTime(startTime);
For more info, read the Stopwatch in .NET 7.0 documentation .有关详细信息，请阅读.NET 7.0 文档中的秒表。
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