[英]How do i create a variable firebase database name?
I want to search a variable data using the Firebase database.我想使用 Firebase 数据库搜索变量数据。
My problem.我的问题。 I'm using an edit text.我正在使用编辑文本。 I want to show the value of the database I wrote here as a text.我想将我在这里写的数据库的值显示为文本。 I only managed to do that.我只能做到这一点。 But under the data in my database, there is a data named "name" that works.但是在我的数据库中的数据下,有一个名为“name”的数据有效。
-L3131131313 112: "ambulans" name: "ambulans" -L3131131313 112:“救护车”名称:“救护车”
When I call "112" with Edit Text, it gives me an "ambulance".当我用编辑文本呼叫“112”时,它给了我一辆“救护车”。 But I want to do it when there's no database named "name."但是当没有名为“name”的数据库时,我想这样做。
This is what should be.这是应该的。 The value of "112" should be "ambulance." “112”的值应该是“救护车”。
-L3131131313 112: "ambulans" -L3131131313 112:“救护车”
The value "112" will be continuously variable.值“112”将是连续可变的。 For example, "110", "200", "352", etc. I would like to see the value opposite to the data I'm querying with Edit Text, but I failed.例如,“110”、“200”、“352”等。我想看到与我使用“编辑文本”查询的数据相反的值,但我失败了。 I'd appreciate it if you could help.如果您能提供帮助,我将不胜感激。 Sorry for my bad english.对不起,我的英语不好。
public class MainActivity extends AppCompatActivity {
EditText Search_Edit_Text;
Button Search_Button;
RecyclerView Search_Contact_List;
DatabaseReference mUserDatabase;
FirebaseRecyclerOptions<CategoryItem> options,options2;
FirebaseRecyclerAdapter<CategoryItem,CategoryViewHolder> adapter;
Query firebaseSearchQuery;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mUserDatabase = FirebaseDatabase.getInstance().getReference().child("database");
Search_Edit_Text = (EditText) findViewById(R.id.Search_Edit_Text);
Search_Button = (Button) findViewById(R.id.Search_Button);
Search_Contact_List = (RecyclerView) findViewById(R.id.Search_Contact_List);
Search_Contact_List.setHasFixedSize(true);
GridLayoutManager gridLayoutManager = new GridLayoutManager(getBaseContext(),2);
Search_Contact_List.setLayoutManager(gridLayoutManager);
Search_Button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
String searchText = Search_Edit_Text.getText().toString();
firebaseUserSearch(searchText);
}
});
private void firebaseUserSearch(String searchText) {
Toast.makeText(MainActivity.this, "Started Search",
Toast.LENGTH_LONG).show();
firebaseSearchQuery = mUserDatabase.orderByChild(searchText).startAt("").endAt("" + "\uf8ff");
options2 = new FirebaseRecyclerOptions.Builder<CategoryItem>()
.setQuery(firebaseSearchQuery,CategoryItem.class)
.build();
adapter = new FirebaseRecyclerAdapter<CategoryItem,
CategoryViewHolder>(options2) {
@Override
protected void onBindViewHolder(@NonNull final CategoryViewHolder holder, int position, @NonNull final CategoryItem model) {
}
@NonNull
@Override
public CategoryViewHolder onCreateViewHolder(@NonNull ViewGroup parent, int viewType) {
View itemView = LayoutInflater.from(parent.getContext())
.inflate(R.layout.list_layout,parent,false);
return new CategoryViewHolder(itemView);
}
};
setCategory();
}
private void setCategory() {
adapter.startListening();
Search_Contact_List.setAdapter(adapter);
}
My Category Item我的类别项目
public class CategoryItem {
public String name;
public CategoryItem() {
}
public CategoryItem(String name) {
this.name = name;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
UPDATE更新
I've solved some of my problems.我已经解决了我的一些问题。 The sample database I will use is as follows.我将使用的示例数据库如下。 Now I want to do, but I can not produce a solution.现在我想做,但我无法产生解决方案。
There will be two or more sub-database sets in our database.我们的数据库中将有两个或多个子数据库集。 For example, I will use this database name "+90 505 696 1234" twice.例如,我将使用这个数据库名称“+90 505 696 1234”两次。 The value of this database is "A" and the value of "AA" in the other set.这个数据库的值为“A”,另一个集合中的值为“AA”。 When I call this phone number with Edit Text, I want it to give me the value "A" and "AA".当我使用 Edit Text 拨打这个电话号码时,我希望它给我值“A”和“AA”。 But I can't make it.但我做不到。 Because the CategoryItem class I created is not a variable.因为我创建的 CategoryItem 类不是变量。 I used the name as String value in CategoryItem.我在 CategoryItem 中使用名称作为字符串值。 I call it with getName ().我用 getName() 调用它。 But if this value is fixed, it works.但是如果这个值是固定的,它就可以工作。 I cannot find a solution because the user will search for different database names with the help of edit text.我找不到解决方案,因为用户将在编辑文本的帮助下搜索不同的数据库名称。 I'il be very happy if you can help.如果你能帮忙我会很高兴的
My Firebase Database我的 Firebase 数据库
{
"ContactPhoneNumbers" : {
"-LcaHYcsoGA-VT8yvgGf" : {
"+90 505 696 1234" : "A",
"+90 506 854 2345" : "B",
"+90 530 408 3456" : "C",
"+90 535 966 4567" : "D",
"+90 536 782 5678" : "E",
"+90 546 934 67 89" : "F",
"+905304080001" : "G",
"+905316910002" : "H",
"+905359660003" : "I",
"+905367820004" : "J",
"+905425420005" : "K",
"+905469340006" : "L",
"05056960007" : "M"
},
"-LcaH_gtgarJwbY5-C08" : {
"+90 505 696 1234" : "AA",
"+90 506 854 2345" : "BB",
"+90 530 408 3456" : "CAC",
"+90 535 966 4567" : "AAA",
"+90 536 782 5678" : "CAB",
"+90 546 934 67 89" : "BB",
"+905304080001" : "A",
"+905316910002" : "BBB",
"+905359660003" : "DDD",
"+905367820004" : "EEE",
"+905425420005" : "FFF",
"+905469340006" : "L",
"05056960007" : "M"
}
}
}
My CategoryItem.java我的 CategoryItem.java
public class CategoryItem {
public String name ;
public CategoryItem() {
}
public CategoryItem(String name) {
this.name = name;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
I want to search a variable data using the Firebase database.我想使用 Firebase 数据库搜索变量数据。
My problem.我的问题。 I'm using an edit text.我正在使用编辑文本。 I want to show the value of the database I wrote here as a text.我想将我在这里写的数据库的值显示为文本。 I only managed to do that.我只能做到这一点。 But under the data in my database, there is a data named "name" that works.但是在我的数据库中的数据下,有一个名为“name”的数据有效。
-L3131131313 112: "ambulans" name: "ambulans" -L3131131313 112:“救护车”名称:“救护车”
When I call "112" with Edit Text, it gives me an "ambulance".当我用编辑文本呼叫“112”时,它给了我一辆“救护车”。 But I want to do it when there's no database named "name."但是当没有名为“name”的数据库时,我想这样做。
This is what should be.这是应该的。 The value of "112" should be "ambulance." “112”的值应该是“救护车”。
-L3131131313 112: "ambulans" -L3131131313 112:“救护车”
The value "112" will be continuously variable.值“112”将是连续可变的。 For example, "110", "200", "352", etc. I would like to see the value opposite to the data I'm querying with Edit Text, but I failed.例如,“110”、“200”、“352”等。我想看到与我使用“编辑文本”查询的数据相反的值,但我失败了。 I'd appreciate it if you could help.如果您能提供帮助,我将不胜感激。 Sorry for my bad english.对不起,我的英语不好。
public class MainActivity extends AppCompatActivity {
EditText Search_Edit_Text;
Button Search_Button;
RecyclerView Search_Contact_List;
DatabaseReference mUserDatabase;
FirebaseRecyclerOptions<CategoryItem> options,options2;
FirebaseRecyclerAdapter<CategoryItem,CategoryViewHolder> adapter;
Query firebaseSearchQuery;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mUserDatabase = FirebaseDatabase.getInstance().getReference().child("database");
Search_Edit_Text = (EditText) findViewById(R.id.Search_Edit_Text);
Search_Button = (Button) findViewById(R.id.Search_Button);
Search_Contact_List = (RecyclerView) findViewById(R.id.Search_Contact_List);
Search_Contact_List.setHasFixedSize(true);
GridLayoutManager gridLayoutManager = new GridLayoutManager(getBaseContext(),2);
Search_Contact_List.setLayoutManager(gridLayoutManager);
Search_Button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
String searchText = Search_Edit_Text.getText().toString();
firebaseUserSearch(searchText);
}
});
private void firebaseUserSearch(String searchText) {
Toast.makeText(MainActivity.this, "Started Search",
Toast.LENGTH_LONG).show();
firebaseSearchQuery = mUserDatabase.orderByChild(searchText).startAt("").endAt("" + "\uf8ff");
options2 = new FirebaseRecyclerOptions.Builder<CategoryItem>()
.setQuery(firebaseSearchQuery,CategoryItem.class)
.build();
adapter = new FirebaseRecyclerAdapter<CategoryItem,
CategoryViewHolder>(options2) {
@Override
protected void onBindViewHolder(@NonNull final CategoryViewHolder holder, int position, @NonNull final CategoryItem model) {
}
@NonNull
@Override
public CategoryViewHolder onCreateViewHolder(@NonNull ViewGroup parent, int viewType) {
View itemView = LayoutInflater.from(parent.getContext())
.inflate(R.layout.list_layout,parent,false);
return new CategoryViewHolder(itemView);
}
};
setCategory();
}
private void setCategory() {
adapter.startListening();
Search_Contact_List.setAdapter(adapter);
}
My Category Item我的类别项目
public class CategoryItem {
public String name;
public CategoryItem() {
}
public CategoryItem(String name) {
this.name = name;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
UPDATE更新
I've solved some of my problems.我已经解决了我的一些问题。 The sample database I will use is as follows.我将使用的示例数据库如下。 Now I want to do, but I can not produce a solution.现在我想做,但我无法产生解决方案。
There will be two or more sub-database sets in our database.我们的数据库中将有两个或多个子数据库集。 For example, I will use this database name "+90 505 696 1234" twice.例如,我将使用这个数据库名称“+90 505 696 1234”两次。 The value of this database is "A" and the value of "AA" in the other set.这个数据库的值为“A”,另一个集合中的值为“AA”。 When I call this phone number with Edit Text, I want it to give me the value "A" and "AA".当我使用 Edit Text 拨打这个电话号码时,我希望它给我值“A”和“AA”。 But I can't make it.但我做不到。 Because the CategoryItem class I created is not a variable.因为我创建的 CategoryItem 类不是变量。 I used the name as String value in CategoryItem.我在 CategoryItem 中使用名称作为字符串值。 I call it with getName ().我用 getName() 调用它。 But if this value is fixed, it works.但是如果这个值是固定的,它就可以工作。 I cannot find a solution because the user will search for different database names with the help of edit text.我找不到解决方案,因为用户将在编辑文本的帮助下搜索不同的数据库名称。 I'il be very happy if you can help.如果你能帮忙我会很高兴的
My Firebase Database我的 Firebase 数据库
{
"ContactPhoneNumbers" : {
"-LcaHYcsoGA-VT8yvgGf" : {
"+90 505 696 1234" : "A",
"+90 506 854 2345" : "B",
"+90 530 408 3456" : "C",
"+90 535 966 4567" : "D",
"+90 536 782 5678" : "E",
"+90 546 934 67 89" : "F",
"+905304080001" : "G",
"+905316910002" : "H",
"+905359660003" : "I",
"+905367820004" : "J",
"+905425420005" : "K",
"+905469340006" : "L",
"05056960007" : "M"
},
"-LcaH_gtgarJwbY5-C08" : {
"+90 505 696 1234" : "AA",
"+90 506 854 2345" : "BB",
"+90 530 408 3456" : "CAC",
"+90 535 966 4567" : "AAA",
"+90 536 782 5678" : "CAB",
"+90 546 934 67 89" : "BB",
"+905304080001" : "A",
"+905316910002" : "BBB",
"+905359660003" : "DDD",
"+905367820004" : "EEE",
"+905425420005" : "FFF",
"+905469340006" : "L",
"05056960007" : "M"
}
}
}
My CategoryItem.java我的 CategoryItem.java
public class CategoryItem {
public String name ;
public CategoryItem() {
}
public CategoryItem(String name) {
this.name = name;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
}
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