定义基于对象的TypeScript类型？

Question

Is it possible to define a type based on an instance of an object?

I don't want to define an interface first, I want a generic type that takes a value as the input, not a type.

Example:

const someObject: any = {
  foo: "",
  bar: ""
}

// should show error because "bar" property is missing
const someOtherObject: SameShape<someObject> {
  foo: ""
}

A flat object structure is all I need at the moment. So something like this (except something that works):

type SameShape = { [key in keyof someObject]: string }

Answer 1

Use typeof operator.

// This is valid
const someOtherObject: SameShape<typeof someObject> 

type SameShape<T> = { [key in keyof T]: string }

But you need to remove that any in someObject: any first.

Now for you use case, following is enough, you don't need an extra SameShape

const someOtherObject: typeof someObject = {/* ... */}