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使用ENUM将默认值设为不合格

[英]Use ENUM to default value to ineligible

I have following code that handles EligibilityType : 我有以下代码处理EligibilityType

public enum EligibilityType {

    E (EligibilityTypeEnum.ELIGIBLE),
    I (EligibilityTypeEnum.INELIGIBLE);

    private final EligibilityTypeEnum eligibilityTypeEnum;

    private EligibilityType(EligibilityTypeEnum eligibilityTypeEnum) {
        this.eligibilityTypeEnum = eligibilityTypeEnum;
    }

    public EligibilityTypeEnum toEligibilityTypeEnum() {
        return eligibilityTypeEnum;
    }
}

I learned that everything that is not of value "E" should be set to EligibilityTypeEnum.INELIGIBLE . 我了解到,所有不具有“ E”值的内容都应设置为EligibilityTypeEnum.INELIGIBLE

And this is how I am calling it: 这就是我所说的:

...
List<Workout> workouts = workoutResults.getWorkout();
for(int i = 0; i< workouts.size(); ++i) {
    ...
    stin.getWorkouts().get(i).setEligibilityType(EligibilityType.valueOf(workouts.get(i).getRecommendation()).toEligibilityTypeEnum());
    ...
}

Right now the code blows up if workouts.get(i).getRecommendation() returns "C". 现在,如果workouts.get(i).getRecommendation()返回“ C”,该代码将workouts.get(i).getRecommendation()

Does anyone see any other way of achieving this except try-catch ? 除了try-catch之外,还有人看到其他实现此目的的方法吗?

Is there a way to set a default value in enum? 有没有办法在枚举中设置默认值?

you can have in EligibilityType a map with all possible values 您可以在EligibilityType拥有包含所有可能值的地图

public static final Map<String, EligibilityType> ALL_MAP = Arrays.stream(values())
            .collect(Collectors.toMap(Enum::toString, Function.identity()));

then you can handle gracefully the default case 那么您就可以优雅地处理默认情况

EligibilityType.ALL_MAP.getOrDefault(someString, EligibilityType.DEFAULT)

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