在熊猫中使用df.drop时，使行的索引移动

Question

I am working on a program where I take a random value find coordinates that are similar in distance to them add them to a group and remove them from the Dataframe.

So assuming I have the list of these coordinates

They should be grouped so that index

• 0 and 1 are together
• 2 and 4 are together
• 3 is alone

The issue im running into is that the initial index is chosen at random for the count of rows using

randInt = random.randint(0, count_row - 1)

and when I remove a coordinate point from the Dataframes it doesn't shift the others up like the following picture.

I am currently deleting the points using the following commands.

The random index chosen is added to a list then removed from Dataframe using

df.drop(current, inplace=True)

Then if a point is within a certain distance it is added to the list and removed using (where index is the index of the point in the Dataframes when looping through)

df.drop(index, inplace=True)

So my question is, how can I make it so that when a point its removed it shifts the Ids up with it?

Answer 1

尝试重置索引

df = df.reset_index(drop=True)