[英]TypeScript - Using Generics to Create a Custom Type
I'm using an intermediary step for creating a type that has property keys that must be the same as the keys of a specified interface 我正在使用一个中间步骤来创建一个类型 ,该类型的属性键必须与指定接口的键相同
// 1. Create Interface
interface IDetail {
name: string;
enabled: boolean;
}
// 2. Create a 'type' that has properties that match the properties of an interface
type DetailType = {
[key in keyof IDetail]: any
}
// 3. Apply the type to an object literal
const control: DetailType = {
name: [],
enabled: []
}
I repeat this pattern quite often, and I'm wondering is there a way to generalize the 2nd step - possibly using generics ? 我经常重复这种模式,我想知道是否有一种方法可以概括第二步-可能使用泛型 ?
Well you can just make your type generic: 好吧,您可以使您的类型通用:
interface IDetail {
name: string;
enabled: boolean;
}
type Generic<T> = { [key in keyof T]: any };
const controlGeneric: Generic<IDetail> = {
name: [],
enabled: []
};
You can make a special generic type: 您可以创建一个特殊的泛型类型:
type WrapMyType<T, V> = { [key in keyof T]: V };
const control: WrapMyType<IDetail, any> = {
name: [],
enabled: [],
};
If you don't want to lose the types you can use this approach 如果您不想丢失类型,可以使用此方法
type DetailType<T> = { [key in keyof T]: T[key] };
const control: DetailType<IDetail> = {
name: [], // must be string
enabled: [] // must be boolean
}
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