使用JPA 2.0 Criteria API执行类似Long值的操作

Question

I have following data structure stored in my database:

public class Company{
    ...
    Long companyNumber;
    ...
}

Now I want to perform Like search on this particular column. As stated in some similar questions , I'm trying to do a .as(String.class) on criteria builder inside my specification class:

public class CompanySpecification implements Specification<Company> { 

private String searchFilter;

@Override
public Predicate toPredicate(Root<Company> root, CriteriaQuery<?> criteriaQuery, CriteriaBuilder criteriaBuilder) {
    ...
    orPredicates.add(criteriaBuilder.like(root.get(Company_.companyNumber).as(String.class), "%" + searchFilter + "%"));
    ...
}

However the following implementation works only on the first character. For example:

If is search for string value 9 , this predicate returns all Companies where 9 is part of companyNumber ( 1119 , 1191 , 1911 , 9111 ) but when I search for values with more then one character, no results are found. For example: if i search for 91 , no results are found even though there are companies in db with company numbers containing 91 : 1191 , 1911 , 9111 . I'm stuck on this, could you please point where have i made a mistake?

EDIT

added definition of searchFilter , search filter is set via constructor:

CompanySpecification companySpecification = new CompanySpecification(searchParameter);

where search parameter is passed as request parameter

Answer 1

原来上面的代码工作正常，问题是搜索是用分页执行的，请求页面的数量高于最大结果，因此返回的结果列表为空。