[英]How to manually add objects to a Django model using a for loop?
relatively new to Python and very new to Django so looking for some help with this. 对Python而言相对较新,而对Django而言则相对较新,因此需要一些帮助。
I'm trying to create a user rank-up system similar to what you'd find in an role-playing game (ie the user gains levels by getting experience points) 我正在尝试创建一个与角色扮演游戏中类似的用户升级系统(即,用户通过获得经验值来获得等级)
So far I have an app in my project with this simple model within its models.py. 到目前为止,我在我的项目中有一个应用程序,该应用程序的models.py中包含此简单模型。 I've already ran migrations and this currently empty table is sat in my database:
我已经进行了迁移,并且此当前为空的表位于我的数据库中:
class UserLevel(models.Model):
level_rank = models.IntegerField()
xp_threshold = models.IntegerField()
Now what I want to do is add levels 1 to 100 (integers) to level_rank. 现在我要做的是将级别1到100(整数)添加到level_rank。 So there would be 100 instances.
因此,将有100个实例。 Level 100 would be the max level.
最高等级为100。
In addition, the xp_threshold would increment by 50% each level. 另外,xp_threshold将每级增加50%。
So for example, level 1 would have an xp_threshold of 100, level 2 would have 150, level 3 would have 225 and so on. 因此,例如,级别1的xp_threshold为100,级别2的值为150,级别3的值为225,依此类推。
I don't particular care how the numbers are rounded. 我不在乎数字如何取整。
I'm using Django v2.0.13 我正在使用Django v2.0.13
So far, I have this: 到目前为止,我有这个:
class UserLevel(models.Model):
level_rank = models.IntegerField()
xp_threshold = models.IntegerField()
levels_range = range(1,101)
for level in levels_range:
UserLevel.objects.create(level_rank=level)
But this is giving me a NameError saying that UserLevel is not defined. 但这给了我一个NameError,说UserLevel没有定义。
I know I could manually just pump this data into Django's admin but that's going to take a looooong time for 100 levels and I know there's a better way to do this. 我知道我可以手动将这些数据泵送到Django的管理员中,但是要花100个级别才能花费很长时间,而且我知道有一个更好的方法。
Any ideas? 有任何想法吗?
Thanks! 谢谢!
It is about Python not Django. 这是关于Python而不是Django。 Simply you can't do this in Python
简而言之,您无法在Python中做到这一点
class MyAwesomeClass:
a = 1
print(a)
print(MyAwesomeClass.a)
this will throw throw NameError on 4. line 这将在第4行上抛出NameError
Instead use shell to create data like so python manage.py shell
而是使用shell创建数据,例如
python manage.py shell
from yourapp.models import UserLevel
UserLevel.objects.bulk_create([UserLevel(level_rank=level) for level in range(1, 101)])
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